466 reputation
211
bio website cvgmt.sns.it/HomePages/cm
location Pisa, Italy
age 45
visits member for 3 years, 3 months
seen Aug 19 at 11:52
I am an analysis researcher at the Scuola Normale Superiore di Pisa

Aug
18
comment Reference/proof for parabolic Holder spaces property
Thanks. In Krylov book mentioned there such property is given as an exercise. I am going for a crash course in parabolic Holder spaces...
Aug
18
revised Reference/proof for parabolic Holder spaces property
added 62 characters in body
Aug
18
revised Examples on small cut radius of totally convex set in non-negatively curved manifold
deleted 6 characters in body
Aug
18
accepted Closed geodesic loops around points in compact manifolds
Aug
17
asked Reference/proof for parabolic Holder spaces property
Jul
2
awarded  Curious
Jun
1
awarded  Yearling
Jun
2
awarded  Yearling
May
20
asked Closed geodesic loops around points in compact manifolds
Feb
25
comment Topology of ${\mathbb R}^n$
@Sam/Wlodzimierz - After your (Sam) comment on contractibility, it seems to me that the point is exactly that... the problem can also be reduced to show that a compact $(n-1)$-dimensional submanifold embedded in ${\mathbb R}^n$ cannot be retracted (in itself) on some ${\mathbb S}^m$, with $m\leq n-2$ ($m$ is actually the dimension of the factor N minus 1). I am wondering whether the fact that the hypersurface "disconnects" ${\mathbb R}^n$ and the "final" sphere ${\mathbb S}^m$ instead does not, can be used (at least in the differential case) to get a conclusion without using (co)-homology.
Feb
22
comment Topology of ${\mathbb R}^n$
no problem Zev
Feb
22
comment Topology of ${\mathbb R}^n$
I had in mind something in this spirit. I was just wondering if it was possible something easier, the question came from one of my undergraduate students.
Feb
22
asked Topology of ${\mathbb R}^n$
Feb
5
comment analysis of the regularity using Hormander condition
Possibly, you should say in what spaces you are looking for uniqueness/regularity/continuous dependence
Jan
29
comment Vitali sets of full outer measure
yes, exactly .
Jan
29
accepted Vitali sets of full outer measure
Jan
29
comment Vitali sets of full outer measure
Nice answer Robert! Thanks
Jan
29
asked Vitali sets of full outer measure
Jan
29
accepted Cutlocus and conjugate points
Jan
25
awarded  Commentator