bio | website | cvgmt.sns.it/HomePages/cm |
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location | Pisa, Italy | |
age | 45 | |
visits | member for | 3 years, 3 months |
seen | Aug 19 at 11:52 | |
stats | profile views | 913 |
I am an analysis researcher at the Scuola Normale Superiore di Pisa
Aug
18 |
comment |
Reference/proof for parabolic Holder spaces property
Thanks. In Krylov book mentioned there such property is given as an exercise. I am going for a crash course in parabolic Holder spaces... |
Aug
18 |
revised |
Reference/proof for parabolic Holder spaces property
added 62 characters in body |
Aug
18 |
revised |
Examples on small cut radius of totally convex set in non-negatively curved manifold
deleted 6 characters in body |
Aug
18 |
accepted | Closed geodesic loops around points in compact manifolds |
Aug
17 |
asked | Reference/proof for parabolic Holder spaces property |
Jul
2 |
awarded | Curious |
Jun
1 |
awarded | Yearling |
Jun
2 |
awarded | Yearling |
May
20 |
asked | Closed geodesic loops around points in compact manifolds |
Feb
25 |
comment |
Topology of ${\mathbb R}^n$
@Sam/Wlodzimierz - After your (Sam) comment on contractibility, it seems to me that the point is exactly that... the problem can also be reduced to show that a compact $(n-1)$-dimensional submanifold embedded in ${\mathbb R}^n$ cannot be retracted (in itself) on some ${\mathbb S}^m$, with $m\leq n-2$ ($m$ is actually the dimension of the factor N minus 1). I am wondering whether the fact that the hypersurface "disconnects" ${\mathbb R}^n$ and the "final" sphere ${\mathbb S}^m$ instead does not, can be used (at least in the differential case) to get a conclusion without using (co)-homology. |
Feb
22 |
comment |
Topology of ${\mathbb R}^n$
no problem Zev |
Feb
22 |
comment |
Topology of ${\mathbb R}^n$
I had in mind something in this spirit. I was just wondering if it was possible something easier, the question came from one of my undergraduate students. |
Feb
22 |
asked | Topology of ${\mathbb R}^n$ |
Feb
5 |
comment |
analysis of the regularity using Hormander condition
Possibly, you should say in what spaces you are looking for uniqueness/regularity/continuous dependence |
Jan
29 |
comment |
Vitali sets of full outer measure
yes, exactly . |
Jan
29 |
accepted | Vitali sets of full outer measure |
Jan
29 |
comment |
Vitali sets of full outer measure
Nice answer Robert! Thanks |
Jan
29 |
asked | Vitali sets of full outer measure |
Jan
29 |
accepted | Cutlocus and conjugate points |
Jan
25 |
awarded | Commentator |