Yingfei Gu
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Registered User
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A physics(condensed matter theory) student. Interested in topology and geometry.
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Apr 8 |
asked | Manifold with nonzero pontryagin number? |
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Dec 11 |
comment |
Homotopy $\pi_4(SU(2))=Z_2$ Thank you! This is a very very nice answer~ |
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Dec 11 |
awarded | ● Scholar |
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Dec 11 |
awarded | ● Supporter |
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Dec 9 |
comment |
Homotopy $\pi_4(SU(2))=Z_2$ @Alexander, got it. Thanks for reminding. |
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Dec 9 |
comment |
Homotopy $\pi_4(SU(2))=Z_2$ BTW, thank you for inform me of the misuse of $\Pi,\pi$. |
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Dec 9 |
comment |
Homotopy $\pi_4(SU(2))=Z_2$ Thank you for your responses. I guess the best way for me to understand is from the generator of $\pi_4(S^3)$. I googled and get some visualization of Hopf map, but now can you give me some "visualization" or explanation on the "suspension homomorphism". @Sm Nlen @Tyler Lawson |
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Dec 9 |
awarded | ● Editor |
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Dec 9 |
revised |
Homotopy $\pi_4(SU(2))=Z_2$ edited body; edited title |
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Dec 9 |
awarded | ● Student |
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Dec 9 |
asked | Homotopy $\pi_4(SU(2))=Z_2$ |
