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location  Pasadena  
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You can contact me at gjergjiz at gmail.com
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awarded  Enlightened 
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awarded  Nice Answer 
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comment 
Numerical evidence and argument against Littlewood conjecture
@StefanKohl yes, I realized that was bad phrasing. The quote was referring to "below $\liminf \epsilon$". But the point was that all this is irrelevant to the question at hand :) 
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answered  How to construct a graph with arbitrarily large girth and large chromatic number? 
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Isoceles Triangles on a Grid Proof
It would help if you stated the source of the question. The result is true, and it's a matter of finding a particular tiling invariant. I wouldn't dismiss the question as obviously inappropriate, but perhaps the way it's worded seems to imply that it's a homework problem. 
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awarded  Enlightened 
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awarded  Nice Answer 
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revised 
Modular forms and “too many symmetries”
Added an arxiv tag 
Dec 18 
comment 
Numerical evidence and argument against Littlewood conjecture
I don't see any contradiction with that article. Only finitely many elements of a sequence can be below the $\liminf$, however, it is possible for infinitely many to be above it. 
Dec 18 
comment 
Numerical evidence and argument against Littlewood conjecture
@joro, not quite, because although $f(n)$ is very large for some values of $n$ which you considered, it will be very small for the values I mentioned above. That's enough to imply $\lim inf=0$. 
Dec 18 
answered  Numerical evidence and argument against Littlewood conjecture 
Dec 17 
answered  Modular forms and “too many symmetries” 
Dec 17 
awarded  Notable Question 
Dec 16 
revised 
Polynomials of low degree that clone polynomials of higher degree
added 250 characters in body 
Dec 16 
comment 
Polynomials of low degree that clone polynomials of higher degree
@Turbo it works for any product of linear forms. This is essentially the argument Alon used to prove the Komjath conjecture about covering the hypercube with hyperplanes. 
Dec 16 
awarded  Nice Answer 
Dec 16 
answered  A proposition on cyclic group 
Dec 16 
comment 
Polynomials of low degree that clone polynomials of higher degree
The proof would work the same way for all such polynomials. Try to work out an example by hand, the argument is much simpler than my notation makes it seem. 
Dec 16 
answered  Polynomials of low degree that clone polynomials of higher degree 
Dec 16 
answered  Zeros of the derivative of Riemann's $\xi$function 