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You can contact me at gjergjiz at gmail.com


1d
awarded  Enlightened
1d
awarded  Nice Answer
2d
comment Numerical evidence and argument against Littlewood conjecture
@StefanKohl yes, I realized that was bad phrasing. The quote was referring to "below $\liminf -\epsilon$". But the point was that all this is irrelevant to the question at hand :)
2d
answered How to construct a graph with arbitrarily large girth and large chromatic number?
2d
comment Isoceles Triangles on a Grid Proof
It would help if you stated the source of the question. The result is true, and it's a matter of finding a particular tiling invariant. I wouldn't dismiss the question as obviously inappropriate, but perhaps the way it's worded seems to imply that it's a homework problem.
2d
awarded  Enlightened
2d
awarded  Nice Answer
2d
revised Modular forms and “too many symmetries”
Added an arxiv tag
Dec
18
comment Numerical evidence and argument against Littlewood conjecture
I don't see any contradiction with that article. Only finitely many elements of a sequence can be below the $\liminf$, however, it is possible for infinitely many to be above it.
Dec
18
comment Numerical evidence and argument against Littlewood conjecture
@joro, not quite, because although $f(n)$ is very large for some values of $n$ which you considered, it will be very small for the values I mentioned above. That's enough to imply $\lim inf=0$.
Dec
18
answered Numerical evidence and argument against Littlewood conjecture
Dec
17
answered Modular forms and “too many symmetries”
Dec
17
awarded  Notable Question
Dec
16
revised Polynomials of low degree that clone polynomials of higher degree
added 250 characters in body
Dec
16
comment Polynomials of low degree that clone polynomials of higher degree
@Turbo it works for any product of linear forms. This is essentially the argument Alon used to prove the Komjath conjecture about covering the hypercube with hyperplanes.
Dec
16
awarded  Nice Answer
Dec
16
answered A proposition on cyclic group
Dec
16
comment Polynomials of low degree that clone polynomials of higher degree
The proof would work the same way for all such polynomials. Try to work out an example by hand, the argument is much simpler than my notation makes it seem.
Dec
16
answered Polynomials of low degree that clone polynomials of higher degree
Dec
16
answered Zeros of the derivative of Riemann's $\xi$-function