zeb
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Registered User
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Jun 11 |
awarded | ● Nice Question |
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Jun 11 |
revised |
Can anyone analyze this misere game? fixed broken links |
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May 28 |
accepted | Sheaf cohomology in non-commutative setup |
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May 28 |
answered | Sheaf cohomology in non-commutative setup |
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May 25 |
comment |
Is it possible to generalize functions like $x^y, \ln x, \sin x, \arctan x$ to surreal numbers or surcomplex numbers? What on earth is this direct integration supposed to be? All you've said about it is that I should not chop the domain into pieces, whatever that means... |
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May 21 |
comment |
objects which can’t be defined without making choices but which end up independent of the choice It seems like now you need to argue that the collection of isomorphism classes of n-step extensions actually forms a set, though. |
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Apr 27 |
comment |
When does the finite union of convex sets have a hole in it? If you have a way test whether intersections of the convex sets are nonempty, you can adapt the solution to this problem: mathoverflow.net/questions/21911/… |
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Apr 25 |
accepted | A divergent series related to the number of divisors of of p-1 |
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Apr 25 |
answered | A divergent series related to the number of divisors of of p-1 |
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Apr 10 |
revised |
Reals with integer powers bounded away from integers? extraneous we |
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Apr 10 |
revised |
Reals with integer powers bounded away from integers? fixed error |
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Apr 10 |
answered | Reals with integer powers bounded away from integers? |
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Mar 28 |
accepted | reverse coin order by swapping pairs? |
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Mar 28 |
revised |
reverse coin order by swapping pairs? hopefully, made it prettier |
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Mar 28 |
answered | reverse coin order by swapping pairs? |
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Mar 16 |
comment |
The four squares theorem from the Gauss-Legendre three squares theorem 0 and 1 are both squares... |
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Feb 19 |
awarded | ● Favorite Question |
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Jan 29 |
comment |
Sets of integers represented by degree zero rational functions The restriction to degree zero doesn't actually matter. If $P$ and $Q$ have different degrees you can always introduce a new variable $z$ and replace $P$ with $P + 4PQz$ and $Q$ with $Q+4PQz$. The new rational function will be degree $0$ and can only be an integer when $z=0$, when $P=0$, or when $P=Q\ne 0$. |
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Jan 24 |
comment |
Is every positive multiple of 6 the sum of two primes? I strongly doubt it. If someone had a proof of the weaker assertion, I can't see any plausible reason that the method wouldn't extend to Goldbach's conjecture itself. |

