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visits | member for | 4 years, 9 months |
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stats | profile views | 1,291 |
Jul 6 |
accepted | is every point of a Berkovich space a Shilov point? |
Jul 4 |
comment |
is every point of a Berkovich space a Shilov point?
oh, yes, you are right of course |
Jul 4 |
comment |
is every point of a Berkovich space a Shilov point?
> This is still not true, but you have to consider subtler things like points of type 4. > if the point is Abhyankar Am I right that after restricting to the Zariski closure of $x$ and extending the scalars so that the base field is maximally complete, one may assume that $x$ is Abhyankar? |
Jul 4 |
revised |
is every point of a Berkovich space a Shilov point?
added 71 characters in body |
Jul 3 |
revised |
is every point of a Berkovich space a Shilov point?
added 1 character in body; added 7 characters in body |
Jul 3 |
asked | is every point of a Berkovich space a Shilov point? |
Jul 2 |
awarded | Inquisitive |
Jul 2 |
awarded | Curious |
Jun 11 |
accepted | group structure on (subsets of) tropicalizations of Abelian varieties |
Jun 6 |
comment |
group structure on (subsets of) tropicalizations of Abelian varieties
so when one takes $K^\times$ and apply valuation to its factor by $q$, is it possible to somehow relate the quotient to the image of the valuation map composed with some embedding of the quotient elliptic curve (or rather an open subset thereof) into $\mathbb{G}_m^2$, say? |
Jun 6 |
comment |
group structure on (subsets of) tropicalizations of Abelian varieties
Thanks for this detailed answer! You have mentioned that as $K^\times$ tropicalises to $\mathbb R$, the quotient tropicalizes to $\mathbb{R}/\mathbb{Z}\mathrm{log}|q|$. What do you mean by "tropicalizes" here? I encountered the following usage of this word: embed into into a torus, then apply valuation map, but it looks like here the map is something else? |
Jun 6 |
asked | group structure on (subsets of) tropicalizations of Abelian varieties |
Mar 26 |
accepted | composition of Puiseux series? |
Mar 26 |
revised |
composition of Puiseux series?
added 257 characters in body |
Mar 26 |
asked | composition of Puiseux series? |
Mar 26 |
accepted | Is there an algorithm to compute efficiently the dessin d'enfant from a Belyi pair? |
Feb 18 |
revised |
base points of multiplicity $>1$
added 12 characters in body |
Feb 17 |
comment |
base points of multiplicity $>1$
Sasha, it is the projectivisation of the relative tangent bundle, i.e. projectivisation the fibrewise kernel of the map induced on the tangent bundles of $X$ and $T$ by the projection $X \to T$. The map $X \to S$ induces a map from the relative tangent bundle to the tangent bundle $TX/T$ of $S$, hence induces a map on projectivisations, this is $\sigma$. And yes, $\mathbb{P}(TX/T)$ is isomorphic to $X$. |
Feb 15 |
accepted | existence and uniqueness of solutions for ODEs in formal power series? |
Feb 13 |
revised |
existence and uniqueness of solutions for ODEs in formal power series?
edited tags |