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May 20 |
comment |
The first eigenvalue of the Schrödinger operator is simple. You are using the elliptic regularity. What happens if the potenital V is not smooth but just bounded? I think the eigenfunctions will not be smooth anymore. Does the statement remeins true for this case or are there counterexamples? |
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May 20 |
revised |
The first eigenvalue of the Schrödinger operator is simple. added 426 characters in body |
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May 20 |
asked | The first eigenvalue of the Schrödinger operator is simple. |
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May 20 |
asked | regularity of eigenfunctions of Schrödinger Operator |
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Apr 4 |
asked | Resolvent of Laplacian |
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Mar 15 |
awarded | ● Scholar |
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Mar 15 |
awarded | ● Supporter |
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Mar 14 |
asked | Stokes theorem for manifolds without orientation? |
