bio | website | pitt.edu/~kaveh |
---|---|---|
location | Pittsburgh | |
age | 39 | |
visits | member for | 2 years, 2 months |
seen | Apr 13 at 4:46 | |
stats | profile views | 196 |
Assistant Prof. at Univ. of Pittsburgh
Apr 13 |
accepted | Fubini-Study metric for an infinite dimensional Hilbert space |
Apr 13 |
accepted | Weil reciprocity vs Artin reciprocity |
Feb 17 |
comment |
Interesting behaviour of Brion's formula under a degenerate change of variables
I actually have been interested in very similar (perhaps the same) question some years ago. I think I can give an algebro-geometric (not combinatorial) argument for why the vertices that are not mapped to the vertices of $\phi(P)$ do not appear in the formula, at least for the case of $P =$ a Gelfand-Zetlin polytope. I would be very much interested to know if you have a combinatorial argument in this case. |
Feb 17 |
awarded | Editor |
Feb 17 |
revised |
Initial ideal of k-th power of an ideal
added 6 characters in body |
Feb 17 |
answered | Initial ideal of k-th power of an ideal |
Nov 4 |
comment |
Continuity of volume of GIT quotients
Thanks a lot Allen. |
Oct 29 |
accepted | Continuity of volume of GIT quotients |
Oct 27 |
awarded | Critic |
Oct 26 |
asked | Continuity of volume of GIT quotients |
Apr 2 |
comment |
Fubini-Study metric for an infinite dimensional Hilbert space
Thanks Ahmed and Alvarez, so definition works as in the finite dimensional case. |
Mar 30 |
asked | Fubini-Study metric for an infinite dimensional Hilbert space |
Mar 25 |
comment |
Initial ideal of k-th power of an ideal
Sorry Youngsu for confusion. |
Mar 25 |
comment |
Initial ideal of k-th power of an ideal
Here by "primary" I mean m-primary where $\mathfrak{m}$ is the maximal ideal generated by $x_1, \ldots, x_n$. Nevertheless if $\mathfrak{n}$ is another maximal ideal and $I$ is $\mathfrak{n}$-primary then $S/I$ is finite dimensional over ${\bf k}$. |
Mar 25 |
comment |
Initial ideal of k-th power of an ideal
Youngsu: It follows from the following observations: $I$ is primary iff $S/I$ is finite dimensional as a vector space over $k$. Since $\dim(S/I) = \dim(S/ in(I))$ it follows that $in(I)$ is also primary. Now for any $k > 0$, $in(I)^k$ should be primary. Thus $S/in(I)^k$ is finite dimensional which implies that $in(I^k) / in(I)^k$ is also finite dimensional. |
Mar 19 |
asked | Initial ideal of k-th power of an ideal |
Feb 17 |
awarded | Yearling |
Aug 1 |
asked | Degree of a variety is well-defined |
May 9 |
comment |
Weil reciprocity vs Artin reciprocity
Thanks guys for the comments. What I meant above is what Dustin also pointed out. |
May 8 |
asked | Weil reciprocity vs Artin reciprocity |