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bio website kellertimo.de/index.html
location Germany
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I am a postdoc of Uwe Jannsen interested in arithmetic geometry, especially Arithmetic of Abelian schemes, their $L$-functions and étale cohomology.

My two recent articles on the Tate-Shafarevich group and the conjecture of Birch-Swinnerton-Dyer for Abelian schemes over higher dimensional bases over finite fields can be found here:

http://arxiv.org/abs/1410.5293 and http://arxiv.org/abs/1410.5294


Oct
21
revised A generalisation of the Birch and Swinnerton-Dyer conjecture
added 196 characters in body
Oct
21
revised Is the Cassels-Tate pairing defined for elliptic curves over function fields?
added 25 characters in body
Oct
21
comment How the equality in the first case is equivalent to the inequality in the last case?
It is on arxiv now, see arxiv.org/abs/1410.5294 (see also arxiv.org/abs/1410.5293).
Oct
21
revised Is the Cassels-Tate pairing defined for elliptic curves over function fields?
added 158 characters in body
Oct
17
revised Is the Cassels-Tate pairing defined for elliptic curves over function fields?
added 81 characters in body
Oct
16
answered Is the Cassels-Tate pairing defined for elliptic curves over function fields?
Oct
7
answered A generalisation of the Birch and Swinnerton-Dyer conjecture
Oct
5
comment How the equality in the first case is equivalent to the inequality in the last case?
@Shpigle: Please wait a few days.
Sep
30
awarded  Explainer
Sep
29
awarded  Popular Question
Sep
24
awarded  Autobiographer
Sep
24
awarded  Nice Answer
Sep
22
asked birational classification of rationally connected 3-folds
Sep
18
comment What are all positive integers n for which the congruence $a^{n+1} \equiv a (mod n)$ holds?
What about $p = 2$?
Sep
18
answered What are all positive integers n for which the congruence $a^{n+1} \equiv a (mod n)$ holds?
Aug
15
comment Tate-Shafarevich groups over finitely generated fields
This is too difficult and would take too long to explain here.
Aug
15
comment Tate-Shafarevich groups over finitely generated fields
I just proved the equality $H^1(X,\mathscr{A}) = \ker(...)$. I am aware that the question is about characteristic $0$.
Aug
15
answered Tate-Shafarevich groups over finitely generated fields
Aug
1
awarded  Necromancer
Jul
20
comment How the equality in the first case is equivalent to the inequality in the last case?
@Shpigle: In the thread "About equivalent statements of the Birch and Swinnerton-Dyer Conjecture", it is said that "When $K$ is a function field over a finite field of +ve characteristic,"