bio | website | |
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location | ||
age | ||
visits | member for | 2 years, 5 months |
seen | Mar 14 at 17:17 | |
stats | profile views | 363 |
Jan 7 |
accepted | Use of Jensen's inequality on a Riemann surface |
Jan 3 |
asked | Use of Jensen's inequality on a Riemann surface |
Dec 6 |
comment |
Spectral measure and Stone's theorem
@MateuszWasilewski: $\lambda $ is any real number. |
Dec 6 |
comment |
Spectral measure and Stone's theorem
Thanks for your answer. However, I would like to get rid of $E$ completely and express the RHS in my equation (1) only in terms of $U$. Also, $U$ depends on $\lambda $ and $UTU^{-1}=M_\lambda $. |
Dec 5 |
comment |
Spectral measure and Stone's theorem
$U_\lambda $ does not commute with $\lambda $. Compare with $\mathcal{F}(-\Delta )\mathcal{F}^{-1}=\xi ^2$ where $\mathcal{F}$ is the Fourier transform. |
Dec 5 |
asked | Spectral measure and Stone's theorem |
Oct 29 |
awarded | Informed |
Oct 29 |
awarded | Tumbleweed |
Oct 9 |
awarded | Caucus |
Sep 6 |
comment |
Trace, eigenvalues and functional calculus
Well, what I actually want to know is if the formula for the trace is true (and at first I did not know if the eigenspaces were finite dimensional in my case). |
Sep 6 |
comment |
Trace, eigenvalues and functional calculus
@András Bátkai: Yes, $\Pi _p$ is the projection onto the point spectrum of $T$. |
Sep 6 |
comment |
Trace, eigenvalues and functional calculus
In this case we can assume all eigenspaces to be finite dimensional. The assumption I have on $f$ is that it should belong to $\mathcal{S}(\mathbb{R})$ (Schwartz space of rapidly decreasing functions). |
Sep 5 |
asked | Trace, eigenvalues and functional calculus |
Aug 29 |
accepted | Why equality of singular supports? |
Aug 29 |
comment |
Why equality of singular supports?
Sorry, I have made an edit. $\nu $ should be a distribution on $\mathbb{R}$. I'm trying to phrase the question in slightly simpler terms than the original. |
Aug 29 |
revised |
Why equality of singular supports?
deleted 2 characters in body |
Aug 29 |
asked | Why equality of singular supports? |
Aug 22 |
accepted | Support of a distribution |
Aug 21 |
asked | Support of a distribution |
Jul 24 |
comment |
Fourier transform of tempered distribution
But it really doesn't matter as I'm interested in the transform only for $\omega \ne 0$. I was just curious. |