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 Mar 20 awarded Curious Jan 7 accepted Use of Jensen's inequality on a Riemann surface Jan 3 asked Use of Jensen's inequality on a Riemann surface Dec 6 comment Spectral measure and Stone's theorem @MateuszWasilewski: $\lambda$ is any real number. Dec 6 comment Spectral measure and Stone's theorem Thanks for your answer. However, I would like to get rid of $E$ completely and express the RHS in my equation (1) only in terms of $U$. Also, $U$ depends on $\lambda$ and $UTU^{-1}=M_\lambda$. Dec 5 comment Spectral measure and Stone's theorem $U_\lambda$ does not commute with $\lambda$. Compare with $\mathcal{F}(-\Delta )\mathcal{F}^{-1}=\xi ^2$ where $\mathcal{F}$ is the Fourier transform. Dec 5 asked Spectral measure and Stone's theorem Oct 29 awarded Informed Oct 29 awarded Tumbleweed Oct 9 awarded Caucus Sep 6 comment Trace, eigenvalues and functional calculus Well, what I actually want to know is if the formula for the trace is true (and at first I did not know if the eigenspaces were finite dimensional in my case). Sep 6 comment Trace, eigenvalues and functional calculus @András Bátkai: Yes, $\Pi _p$ is the projection onto the point spectrum of $T$. Sep 6 comment Trace, eigenvalues and functional calculus In this case we can assume all eigenspaces to be finite dimensional. The assumption I have on $f$ is that it should belong to $\mathcal{S}(\mathbb{R})$ (Schwartz space of rapidly decreasing functions). Sep 5 asked Trace, eigenvalues and functional calculus Aug 29 accepted Why equality of singular supports? Aug 29 comment Why equality of singular supports? Sorry, I have made an edit. $\nu$ should be a distribution on $\mathbb{R}$. I'm trying to phrase the question in slightly simpler terms than the original. Aug 29 revised Why equality of singular supports? deleted 2 characters in body Aug 29 asked Why equality of singular supports? Aug 22 accepted Support of a distribution Aug 21 asked Support of a distribution