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seen Jun 22 '13 at 16:28
PhD Student.

Apr
22
comment Is function from topological group to metric space Borel?
Thanks for your comment. There is something I don't understand. Are you assuming the closure of the identity is not a single point? Is this is necessarily true?
Apr
22
comment Is function from topological group to metric space Borel?
Sure. The multiplication of g is a dynamical system, a rotation in a compact abelian group. I want to construct a dynamical isomorphism from a dynamical system in X to G.
Apr
21
comment Existence of limit measure
Thanks for your comments. Theorem 4.3 talks about two kinds of limits. The other limit is the outer measure constructed in section 3. Theorem 3.3 mentions that the outer measure is Radon (hence every borel set is measurable) if every open set is the countable union of compact sets.
Apr
21
accepted Existence of limit measure
Apr
21
asked Is function from topological group to metric space Borel?
Apr
20
asked Existence of limit measure
Mar
4
accepted Extension of measures from the ball sigma-algebra to the borel sigma-algebra
Feb
28
accepted Weak convergence, and Cesaro convergence (of mu_n (E) ) imply convergence (of mu_n (E))?
Feb
28
asked Extension of measures from the ball sigma-algebra to the borel sigma-algebra
Feb
7
comment Do ergodic isometries have discrete spectrum?
Sure, a theorem by Halmos and Von Neumann state that T is transitive (one dense orbit) and isometric, iff it is topologically isomoprhic to a minimal rotation on a compact abelian group iff T is minimal and has discrete topological spectrum. (topological because in this case the operator associated to the dynamical system is acting on the space of continuous functions. ) A good reference for this is An introduction to ergodic theory by Peter Walters.
Feb
7
asked Do ergodic isometries have discrete spectrum?
Nov
12
comment Weak convergence, and Cesaro convergence (of mu_n (E) ) imply convergence (of mu_n (E))?
Thanks, I was not looking for the case when the cesaro means do not converge. I wanted that as a part of the hypothesis. But I think your counter example works, if you take $x_{n}$=0 only sporadically, then you will have cesaro mean convergence but not convergence.
Nov
12
revised Weak convergence, and Cesaro convergence (of mu_n (E) ) imply convergence (of mu_n (E))?
edited tags
Nov
11
awarded  Editor
Nov
11
revised Weak convergence, and Cesaro convergence (of mu_n (E) ) imply convergence (of mu_n (E))?
added 34 characters in body
Nov
9
asked Weak convergence, and Cesaro convergence (of mu_n (E) ) imply convergence (of mu_n (E))?
Jul
26
awarded  Teacher
Apr
16
answered Proofs that require fundamentally new ways of thinking
Feb
10
comment A system of equations for integers
Yes , that exactly what I meant. by "Given R1, the system has a unique solution." thanks for clearing this out.
Feb
10
accepted A system of equations for integers