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17h

awarded  Revival 
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invariants that can be measured by Local Cohomology
I mean the Faltings annihilator implies Theorem 1. By Faltings annihilator we have $\mathfrak{p} \in Var(\mathfrak{a})$ if and only if $$\mathrm{depth} R_{\mathfrak{p}} + \dim R/\mathfrak{p} < d.$$ The last one is equivalent to $\mathfrak{p} \in nCM(R)$. 
Apr
20 
answered  invariants that can be measured by Local Cohomology 
Jan
11 
answered  Ring with CohenMacaulay canonical module 
Dec
29 
answered  Maximal CohenMacaulay modules of type one 
Dec
11 
comment 
The finiteness of the associated primes of $Ext^i_R(R/I, M)$
the local condition is not important in this question. you can change $\mathbb{Z}[X]$ by $\mathbb{Q}[X,Y,Z]_{(X,Y,Z)}$ and the prime ideals $\{(p,X): p \text{ is prime}\}$ by $\{(X, Y+nZ) : n = 0, 1, ...\}$. 
Dec
11 
answered  The finiteness of the associated primes of $Ext^i_R(R/I, M)$ 
Sep
18 
awarded  Yearling 
Sep
7 
awarded  Nice Question 
Sep
4 
comment 
Gradedirreducible ideals are irreducible?
Thank you Fred, I have a quick look their proof. They used the fact $I$ is irreducible iff the index of reducible of $I$ is one. So their proof need Noetheian condition. My proof is also true for $\mathbb{Z}$graded (I fell it works for $\mathbb{N}^n$graded also). 
Sep
1 
revised 
Is an irreducible ideal in $R$ also irreducible in $R[x]$?
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Sep
1 
revised 
Is an irreducible ideal in $R$ also irreducible in $R[x]$?
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Sep
1 
answered  Gradedirreducible ideals are irreducible? 
Aug
31 
awarded  Custodian 
Aug
31 
reviewed  Approve Is an irreducible ideal in $R$ also irreducible in $R[x]$? 
Aug
31 
comment 
Is an irreducible ideal in $R$ also irreducible in $R[x]$?
I edited my answer more detail (add a Fact). 
Aug
31 
revised 
Is an irreducible ideal in $R$ also irreducible in $R[x]$?
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Aug
28 
revised 
Is an irreducible ideal in $R$ also irreducible in $R[x]$?
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Aug
28 
answered  Is an irreducible ideal in $R$ also irreducible in $R[x]$? 