bio | website | |
---|---|---|
location | Seattle, WA | |
age | 71 | |
visits | member for | 3 years, 6 months |
seen | 52 mins ago | |
stats | profile views | 1,975 |
Contact: rudytoody.AT.comcast.DOT.net
I retired in 2006 and bought Mathematica and a stack of math books with the goal to teach myself to become a world-class mathematician. I am on pace to achieve that goal sometime shortly after the next Ice Age.
I consider myself a Mathematical Mutt (no papers) who occasionally ventures off the back porch to play in the yard with the big dogs.
I donate regularly to the The OEIS Foundation.
When I look at the patterns, I can hear the wheels turning. When I look at the math, I find out the hamsters have died.
Jan 17 |
awarded | Good Question |
Jan 17 |
revised |
$\prod_{n=1}^{\infty} n^{\mu(n)}=\frac{1}{4 \pi ^2}$
added a link |
Jan 11 |
revised |
Fundamental problems whose solution seems completely out of reach
added link to new proof |
Jan 3 |
comment |
Are there any serious investigations of whether “mathematicians do their best work when they're young”?
I think that as an individual becomes more accomplished in her specialty, her employer rewards her with promotions. Each step up that ladder requires more time for non-specialty duties. Therefore, less time for creativity and thus fewer papers. |
Dec 26 |
awarded | Popular Question |
Dec 4 |
comment |
$\zeta(0)$ and the cotangent function
From Edwards, p 12, (1): for $n=0$,$$\zeta (2 n)=\frac{(-1)^{n+1} 2^{2 n-1} \pi ^{2 n} B_{2 n}}{(2 n)!}=\frac{(-1)^{n+1} 2^{2 n-1} \pi ^{2 n}}{(2 n)!}=-\frac{1}{2},$$ with and without the Bernoulli number. |
Sep 11 |
suggested | rejected edit on experimental-mathematics tag wiki excerpt |
Sep 2 |
comment |
Recognize this strange expression from linear algebra?
+1 for index-spaghetti |
Aug 11 |
awarded | Notable Question |
Aug 11 |
revised |
$\prod_{n=1}^{\infty} n^{\mu(n)}=\frac{1}{4 \pi ^2}$
added note that the bug has been corrected in Mathematica V.10 |
Aug 10 |
comment |
Palindromic Patterns of Greatest Divisors $\leq k$
@PerAlexandersson, math.stackexchange.com/q/886041/28555 shows another identity (conjecture) based on the same palindromic divisor sequence. |
Aug 10 |
comment |
Palindromic Patterns of Greatest Divisors $\leq k$
@PerAlexandersson, math.stackexchange.com/q/867135/28555 points to a post that explains how I found it. mathematica.stackexchange.com/q/48452/973 points to the Mathematica code for the recursive routine. |
Aug 10 |
comment |
Palindromic Patterns of Greatest Divisors $\leq k$
Actually, it is not a counter-example. See modified OP. $2193$ is a multiple of 17, inside the 17-seg which shows it is a derangement. |
Aug 10 |
revised |
Palindromic Patterns of Greatest Divisors $\leq k$
added one assumption to constructing the sequence and examining sub-sequences. |
Jul 4 |
revised |
$\prod_{n=1}^{\infty} n^{\mu(n)}=\frac{1}{4 \pi ^2}$
expanded link description |
Jul 4 |
revised |
$\prod_{n=1}^{\infty} n^{\mu(n)}=\frac{1}{4 \pi ^2}$
removed two previous edits which no longer apply to the problem |
Jul 4 |
comment |
$\prod_{n=1}^{\infty} n^{\mu(n)}=\frac{1}{4 \pi ^2}$
@MichaelHardy, thanks for the edit. Thanks for the notation tip. |
Jul 4 |
revised |
$\prod_{n=1}^{\infty} n^{\mu(n)}=\frac{1}{4 \pi ^2}$
added a link to the reciprocal |
May 22 |
accepted | New identity for lcm of the first n integers and the second Chebyshev function |
May 22 |
comment |
New identity for lcm of the first n integers and the second Chebyshev function
@joro, thanks. Somehow, I missed that. |