bio | website | ime.usp.br/~gorodski |
---|---|---|
location | Sao Paulo, Brazil | |
age | 49 | |
visits | member for | 3 years, 6 months |
seen | Nov 20 at 20:05 | |
stats | profile views | 1,448 |
I am a Professor at the University of São Paulo. I have mostly worked on the interaction between Lie groups and geometry, more specifically, Lie transformation groups and submanifold geometry, but I am generally interested in different kinds of problems that can be considered from a geometrical viewpoint.
Oct 23 |
awarded | Necromancer |
Jul 20 |
comment |
Calculation with weights of $E_6$
@Jim: Thanks for your comment. I was sloppy: it was to mean $\Gamma$ is a subquotient of $W$. Anyway, I was wrong about the given motivation. Howe and Umeda's paper "The Capelli identity, the double commutant theorem, and multiplicity-free actions" discusses this representation. |
Jul 20 |
revised |
Calculation with weights of $E_6$
Updated information. |
Jul 17 |
comment |
Is the Duflo polynomial conjecture open?
I guess the main reference is: Journal of Functional Analysis, Volume 117, Issue 1, October 1993, Pages 174–214, Invariant Differential Operators in Symmetrical Spaces. II. Generalized Harish-Chandra Homomorphism, by C. Torossian. |
Jul 12 |
revised |
Calculation with weights of $E_6$
Added possible answer. |
Jul 11 |
revised |
Calculation with weights of $E_6$
Clarified notation. |
Jul 11 |
comment |
Calculation with weights of $E_6$
@Jim: I meant the Coxeter group of type $A_2$. |
Jul 11 |
comment |
Calculation with weights of $E_6$
@Vit: No, it is not. |
Jul 11 |
asked | Calculation with weights of $E_6$ |
Jul 2 |
awarded | Curious |
Jun 24 |
comment |
Is the group of isometries of a homogeneous Riemannian manifold maximal?
Of course. The odd-dimensional sphere $S^{2n+1}$ with the round metric is $O(2n+2)/O(2n+1)$. The subgroup $U(n+1)$ of $O(2n+2)$ acts transitively, and there are $U(n+1)$-invariant metrics which are not round. |
Jun 23 |
comment |
Compact Lie groups with only 3 dimensional cohomology generators
$SO(3)$ is not simply-connected by doubly covered by $S^3$. I think the answer to 1. is only products of $S^3$'s. See "Foundations of Lie Theory and Lie Transformation Groups", edited by V.V. Gorbatsevich, A.L. Onishchik, E.B. Vinberg, p. 127, or Bourbaki. |
Jun 18 |
reviewed | Edit suggested edit on Question about extending a solution to Monge-Ampere solution |
Jun 18 |
revised |
Question about extending a solution to Monge-Ampere solution
changed a few notations |
Jun 11 |
awarded | Citizen Patrol |
Jun 3 |
comment |
Riemann's quote cited by Lakatos: what is the context?
Thanks Ben. This is exactly what Miguel had sent to me, as mentioned in the comments above. |
Jun 3 |
accepted | Riemann's quote cited by Lakatos: what is the context? |
Jun 3 |
awarded | Nice Question |
May 29 |
revised |
Action of a Lie group with finitely many orbits
Fixed notation. |
May 29 |
answered | Action of a Lie group with finitely many orbits |