1,828 reputation
520
bio website maths.lancs.ac.uk/~kania
location Lancaster, United Kingdom
age
visits member for 3 years, 7 months
seen 15 hours ago

Dec
8
comment A commutative Banach algebra with an abundance of discountinuous functions
Sure, thanks, corrected.
Dec
8
revised A commutative Banach algebra with an abundance of discountinuous functions
edited body
Dec
8
comment $2$-D Hlawka inequality
The relevant reference is: D. Yost, $L_1$ contains every two-dimensional normed space, Ann. Polonici Math. 49 (1988), 17–19.
Dec
8
revised A commutative Banach algebra with an abundance of discountinuous functions
added 314 characters in body
Dec
7
answered A commutative Banach algebra with an abundance of discountinuous functions
Dec
7
comment A commutative Banach algebra with an abundance of discountinuous functions
Ali, I suggest rewriting the question using topological terms only. No sophisticated language of operator algebras is necessary here.
Dec
5
revised Banach space modulo a one-dimensional subspace =?
presentation improved
Dec
5
suggested approved edit on Banach space modulo a one-dimensional subspace =?
Dec
4
answered Banach space modulo a one-dimensional subspace =?
Nov
30
revised Functions in “gaps” in Hardy hierarchy
text improved
Nov
30
suggested approved edit on Functions in “gaps” in Hardy hierarchy
Nov
30
comment Simple $Z^{*}$ algebra
The operators with separable range contain a copy of $\ell_\infty$ as a subspace. This is not the case for $K(H)$; dual of each separable subspace of $K(H)$ is separable.
Nov
29
revised Which ordered fields are homeomorphic to their power?
formatting
Nov
29
suggested approved edit on Which ordered fields are homeomorphic to their power?
Nov
29
comment Simple $Z^{*}$ algebra
No, not even as a Banach space.
Nov
29
comment Simple $Z^{*}$ algebra
Each compact operator has countable spectrum. Consider your favourite C*-algebra that has elements with uncountable spectrum...
Nov
29
revised Simple $Z^{*}$ algebra
added 38 characters in body
Nov
29
comment Simple $Z^{*}$ algebra
Oh yes, you are of course right. Thank you for spotting that.
Nov
29
revised Simple $Z^{*}$ algebra
added 2 characters in body
Nov
29
answered Simple $Z^{*}$ algebra