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Tomek Kania
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Jan
26
revised
Is $L_q(X^*)$ complemented in $(L_p(X))^*$?
added 2 characters in body
Jan
26
comment
Is $L_q(X^*)$ complemented in $(L_p(X))^*$?
Gerlad's answer indeed leads to a solution so let me accept it. Full reference is now in the question.
Jan
26
revised
Is $L_q(X^*)$ complemented in $(L_p(X))^*$?
added 291 characters in body
Jan
26
accepted
Is $L_q(X^*)$ complemented in $(L_p(X))^*$?
Jan
6
reviewed
Approve
A question regarding the consistency of Nelson's Predicative Arithmetic
Jan
6
reviewed
Approve
Why do we care about $L^p$ spaces besides $p = 1$, $p = 2$, and $p = \infty$?
Jan
6
revised
On injectivity of the Banach space $C_0(X)$
correcting grammar as my colleague would like to refer to this post in his paper
Dec
16
revised
Is $L_q(X^*)$ complemented in $(L_p(X))^*$?
deleted 99 characters in body
Dec
16
revised
Is $L_q(X^*)$ complemented in $(L_p(X))^*$?
added 4 characters in body
Dec
16
revised
Is $L_q(X^*)$ complemented in $(L_p(X))^*$?
typo
Dec
16
comment
rank 1 projections of finite dimensional von Neumann algebra have the same traces?
Would you mind accepting one of the answers?
Dec
16
asked
Is $L_q(X^*)$ complemented in $(L_p(X))^*$?
Dec
11
reviewed
Approve
References for a minor variant of the Rayleigh quotient
Dec
11
comment
rank 1 projections of finite dimensional von Neumann algebra have the same traces?
@DavePenneys, not to worry! :-)
Dec
11
answered
rank 1 projections of finite dimensional von Neumann algebra have the same traces?
Dec
10
revised
Banach spaces $X$ with $\ell_2(X)$ not isomorphic to $L_2([0,1],X)$
added 8 characters in body
Dec
10
revised
Banach spaces $X$ with $\ell_2(X)$ not isomorphic to $L_2([0,1],X)$
added 11 characters in body
Dec
10
answered
Banach spaces $X$ with $\ell_2(X)$ not isomorphic to $L_2([0,1],X)$
Dec
2
comment
Banach spaces $X$ with $\ell_2(X)$ not isomorphic to $L_2([0,1],X)$
@BillJohnson, how about this: Let $Y$ be a Banach space and let $X=L_2(Y)$. Then $X\cong \ell_2(X)$ and $X\cong L_2(X)$.
Dec
2
comment
Banach spaces $X$ with $\ell_2(X)$ not isomorphic to $L_2([0,1],X)$
@SimonHenry, all Hilbert spaces of the same dimension are isometrically isomorphic due to the Parseval identity.
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