bio | website | maths.lancs.ac.uk/~kania |
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location | Lancaster, United Kingdom | |
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visits | member for | 3 years, 7 months |
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Dec 8 |
comment |
A commutative Banach algebra with an abundance of discountinuous functions
Sure, thanks, corrected. |
Dec 8 |
revised |
A commutative Banach algebra with an abundance of discountinuous functions
edited body |
Dec 8 |
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$2$-D Hlawka inequality
The relevant reference is: D. Yost, $L_1$ contains every two-dimensional normed space, Ann. Polonici Math. 49 (1988), 17–19. |
Dec 8 |
revised |
A commutative Banach algebra with an abundance of discountinuous functions
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Dec 7 |
answered | A commutative Banach algebra with an abundance of discountinuous functions |
Dec 7 |
comment |
A commutative Banach algebra with an abundance of discountinuous functions
Ali, I suggest rewriting the question using topological terms only. No sophisticated language of operator algebras is necessary here. |
Dec 5 |
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Banach space modulo a one-dimensional subspace =?
presentation improved |
Dec 5 |
suggested | approved edit on Banach space modulo a one-dimensional subspace =? |
Dec 4 |
answered | Banach space modulo a one-dimensional subspace =? |
Nov 30 |
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Functions in “gaps” in Hardy hierarchy
text improved |
Nov 30 |
suggested | approved edit on Functions in “gaps” in Hardy hierarchy |
Nov 30 |
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Simple $Z^{*}$ algebra
The operators with separable range contain a copy of $\ell_\infty$ as a subspace. This is not the case for $K(H)$; dual of each separable subspace of $K(H)$ is separable. |
Nov 29 |
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Which ordered fields are homeomorphic to their power?
formatting |
Nov 29 |
suggested | approved edit on Which ordered fields are homeomorphic to their power? |
Nov 29 |
comment |
Simple $Z^{*}$ algebra
No, not even as a Banach space. |
Nov 29 |
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Simple $Z^{*}$ algebra
Each compact operator has countable spectrum. Consider your favourite C*-algebra that has elements with uncountable spectrum... |
Nov 29 |
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Simple $Z^{*}$ algebra
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Nov 29 |
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Simple $Z^{*}$ algebra
Oh yes, you are of course right. Thank you for spotting that. |
Nov 29 |
revised |
Simple $Z^{*}$ algebra
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Nov 29 |
answered | Simple $Z^{*}$ algebra |