unknown

1,518
Reputation
385 views
Is this your account?

Unregistered User 

Name unknown
Member for 2 years
Seen 8 mins ago
Website
Location
Age
May
11
 asked Hodge filtration over $\mathbb Z_p$
May
11
 awarded ● Yearling
May
7
 comment How to prove this algebra is flat?
Thanks for the link, the proof there is nice.
May
7
 asked How to prove this algebra is flat?
Apr
29
 awarded ● Popular Question
Apr
26
 revised algebraic de Rham cohomology of singular varieties
added 53 characters in body
Apr
26
 comment algebraic de Rham cohomology of singular varieties
Right, I was hoping for a reduced one...
Apr
26
 asked algebraic de Rham cohomology of singular varieties
Apr
19
 asked Needless axiom for Grothendieck topologies?
Apr
17
 asked exponential map for finite group schemes?
Apr
12
 asked simple proof of relation between H^1 crystalline and Dieudonne module?
Apr
9
 revised de Rham complex of closed immersion between smooth schemes
added 15 characters in body
Apr
9
 comment de Rham complex of closed immersion between smooth schemes
Sorry, I forgot: $P$ and $Q$ are smooth over $R$.
Apr
9
 asked de Rham complex of closed immersion between smooth schemes
Apr
9
 answered Diagonal map and “infinitesimal points”
Apr
9
 asked smooth algebras and triviality of de Rham complex
Mar
6
 revised Arthur-Clozel Prop 3.1 for Function Fields?
Added statement of Prop 3.1 from Arthur-Clozel; added 7 characters in body
Mar
5
 asked Arthur-Clozel Prop 3.1 for Function Fields?
Feb
28
 asked does this follow from the Fundamental Lemma of Ngo, Laumon, Waldspurger, …?
Feb
24
 revised unramified base change in characteristic p > 0?
added 107 characters in body
Feb
24
 asked unramified base change in characteristic p > 0?
Feb
21
 comment Taking invariants under pro-p-group is exact?
You are right. I said it was not discrete because I was thinking of a general profinite group. It is true that for $P$ a pro-$p$-group acting on a pro-$l$-group, discrete iff continuous. Your observation makes it even simpler to prove that taking invariants under $P$ is an exact functor because after choosing a $\mathbb Z_l$-lattice, $P$ is acting thru a finite $p$-group quotient and then the claim is clear.
Feb
20
 revised Taking invariants under pro-p-group is exact?
added 483 characters in body
Feb
20
 revised Taking invariants under pro-p-group is exact?
added 84 characters in body
Feb
20
 comment Taking invariants under pro-p-group is exact?
Yes, it is easy to see that there always is a $G$-invariant $\mathbb Z_l$-lattice.
Feb
20
 comment Taking invariants under pro-p-group is exact?
Note that I am assuming that the action is continuous (I have amended the statement in my question).
Feb
20
 revised Grothendieck monodromy theorem for l-adic sheaves
deleted 9 characters in body
Feb
20
 comment Taking invariants under pro-p-group is exact?
Note that I am not assuming that the modules are discrete.
Feb
20
 revised Taking invariants under pro-p-group is exact?
added 56 characters in body
Feb
20
 asked Taking invariants under pro-p-group is exact?
Feb
20
 revised Grothendieck monodromy theorem for l-adic sheaves
added 221 characters in body
Feb
19
 asked Grothendieck monodromy theorem for l-adic sheaves
Feb
12
 asked weight monodromy conjecture for curves?
Feb
11
 revised vanishing of spectral term in Arthur-Selberg trace formula for GL(2)?
added 34 characters in body
Feb
11
 asked vanishing of spectral term in Arthur-Selberg trace formula for GL(2)?
Feb
6
 asked intersection cohomology and etale cohomology
Jan
29
 revised cech cohomology in topos
added 6 characters in body
Jan
29
 asked cech cohomology in topos