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11h
awarded  Enlightened
18h
awarded  Nice Answer
20h
revised Remark on Fermat's Last Theorem by Darmon, Diamond and Taylor
typos
22h
revised Remark on Fermat's Last Theorem by Darmon, Diamond and Taylor
typo
22h
revised Remark on Fermat's Last Theorem by Darmon, Diamond and Taylor
typo
23h
revised Remark on Fermat's Last Theorem by Darmon, Diamond and Taylor
clarified again
23h
revised Remark on Fermat's Last Theorem by Darmon, Diamond and Taylor
minor polishing
1d
revised Remark on Fermat's Last Theorem by Darmon, Diamond and Taylor
added 54 characters in body
1d
answered Remark on Fermat's Last Theorem by Darmon, Diamond and Taylor
2d
answered Automorphism group of the affine groups AGL(n,q), ASL(n,q)
Aug
27
awarded  Civic Duty
Aug
27
comment Indecomposable representations of a wreath product
If you stick to irreducible representations of finite dimension, rather than indecomposable, quite a lot of Clifford Theory would seem to go through, since the base group of the wreath product has finite index. So irreducible representations of the wreath product are induced from irreducible representations of direct products of smaller such wreath products corresponding to Young subgroups.
Aug
25
revised An approximate version of $g^2 = e$ for all $g \in G$, implies $G$ is Abelian
Simplified
Aug
24
revised An approximate version of $g^2 = e$ for all $g \in G$, implies $G$ is Abelian
corrected inaccuracy
Aug
24
revised An approximate version of $g^2 = e$ for all $g \in G$, implies $G$ is Abelian
minor rewording
Aug
23
comment transitive action on finite abelian subgroups
There are several typos here, I think. Also, why mention $G$? Why not just say that $K$ is a normal subgroup of $H$?
Aug
23
revised An approximate version of $g^2 = e$ for all $g \in G$, implies $G$ is Abelian
Mentioned connections to Theorems of Frobenius et al
Aug
23
answered An approximate version of $g^2 = e$ for all $g \in G$, implies $G$ is Abelian
Aug
21
awarded  Enlightened
Aug
21
awarded  Nice Answer