Liang Yu

670
Reputation
658 views
Is this your account?

Registered User 

Name Liang Yu
Member for 2 years
Seen yesterday
Website
Location China
Age
A mathematical logician.
Apr
13
awarded  Yearling
Apr
3
comment Complexity of winning strategies for open games (for open player)
Joel, you are right. There should be +1 there.
Feb
12
comment Complexity of winning strategies for open games (for open player)
The rough idea is if the open player has a winning strategy, then for any node $\sigma$ with an even length in the tree $T$, we may define a partial function $f(\sigma)=\inf_n\sup_m f(\sigma ^{\smallfrown} n ^{\smallfrown}m)$ and ensure $f(\emptyset)$ always exists.
Feb
12
comment Complexity of winning strategies for open games (for open player)
This was proved by Andreas Blass in ``A. Blass, Complexity of winning strategies, Discrete Math. 3 (1972), 295–300. "
Feb
9
comment Why has Sacks' “Measure-theoretic uniformity” not been more influential?
He does not. But he used this fact. See the first sentence in section 4 at page 397.
Feb
9
comment Why has Sacks' “Measure-theoretic uniformity” not been more influential?
Actually the results are quite natural from recursion theory point view. Essentially the whole results were just telling some "lowness phenomenon". If we replace $ZF$ with $KP$, then all the results remain true and become totally recursion theoretic.
Feb
9
comment Why has Sacks' “Measure-theoretic uniformity” not been more influential?
The existence of an inaccessible cardinal is used to guarantee that there is a countable ordinal $\alpha$ so that $L_{\alpha}\models ZF+V=L$. Based on this, Sacks can perform a ramified analysis for random forcing to prove the results.
Feb
5
comment Countable admissible ordinals
Ted, you are right. But the proof heavily depends on Jensen's theorem. Actually in the proof of Lemma 4.3, they need Lemma 3.3 that is Jensen's result.
Feb
4
comment Countable admissible ordinals
I asked Prof. Jensen, when he was in NUS, whether he has a model theoretical proof, or by applying Barwise compactness, of his result. He said no. So I guess Harrington's proof must be highly nontrivial.
Feb
4
comment Countable admissible ordinals
Ted, thanks. In Simpon-Weitkamp's paper, it is claimed that Harrington has a model theoretical proof. But where to find it?
Jan
14
revised Definition of HYP in $L_{\omega_1^{CK}}[a]$?
added 104 characters in body
Jan
14
revised Definition of HYP in $L_{\omega_1^{CK}}[a]$?
added 512 characters in body
Jan
13
comment Definition of HYP in $L_{\omega_1^{CK}}[a]$?
I fixed an error in the proof. To show that $x$ is not hyperarithemtic in $N$, we really need Leo's proof.
Jan
13
revised Definition of HYP in $L_{\omega_1^{CK}}[a]$?
I fixed an error in the proof.
Jan
13
revised Definition of HYP in $L_{\omega_1^{CK}}[a]$?
added 4 characters in body
Jan
13
revised Definition of HYP in $L_{\omega_1^{CK}}[a]$?
added 29 characters in body
Jan
13
comment Road to Solovay’s Land.
Having some recursion theory knowledge would also be very helpful to understand Solovay's construction.
Jan
12
comment Definition of HYP in $L_{\omega_1^{CK}}[a]$?
$\Pi^0_1$-singletoness is not a absoluteness notion among the $\omega$-models. Also you have to apply Gandy's basis to get a model not the singleton. I added more details.
Jan
12
revised Definition of HYP in $L_{\omega_1^{CK}}[a]$?
added 262 characters in body; added 11 characters in body
Jan
12
revised Definition of HYP in $L_{\omega_1^{CK}}[a]$?
added 67 characters in body; added 14 characters in body
Jan
12
comment $\omega$-models of $\mathbf{\Sigma^1_1}-DC$ and $\mathbf{\Delta^1_1}-CA$
Check mathoverflow.net/questions/118706/… . It might be helpful for you.
Jan
12
answered Definition of HYP in $L_{\omega_1^{CK}}[a]$?
Dec
15
awarded  Scholar
Dec
15
comment $\Delta^1_2$-well ordering vs $\Delta^1_3$
Andres, thanks! I just got the paper. It seems that Leo also proved the lightface $\Delta^1_3$ one in the same paper.
Dec
15
asked $\Delta^1_2$-well ordering vs $\Delta^1_3$