bio  website  mate.dm.uba.ar/~aldoc9 

location  Buenos Aires  
age  40  
visits  member for  4 years, 10 months 
seen  17 hours ago  
stats  profile views  18,519 
19h

comment 
qth powers and roots of polynomials
@grok, it is best to put information asuch as that you gice in the comment in the question body itself :) 
1d

awarded  Nice Answer 
Aug 16 
accepted  The octonions on a bad day 
Aug 12 
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Identities that connect antipode with multiplication and comultiplication
Those identities are usually described by saying that the antipode map is an antihomomorphism of coalgebras and of algebras, and should be proved in most textbooks on the subject. 
Aug 3 
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when is the restriction $H^2(G,\mathbb{C}^*)\to H^2(K,\mathbb{C}^*)$ surjective?
When G is abelian or, more generally, when K is normal, somrthing can be said by looking at the Leray Hochschild Serre spextral sequence. 
Jul 23 
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Noncommutative HKR theorem
They are not the same. 
Jul 23 
awarded  Nice Answer 
Jul 22 
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Noncommutative HKR theorem
Daniel is right in that a sensible definition of forms in the nc world is through Hochschild homology (or the actual Hochschild complex); this is the point of the noncommutative calculi of Tsygan, Tamarkin and others. It is also true that for other (closely related!) purpuses one uses the definition mentioned by Sasha in his comment above. You can read about it in Max Karoubi's Astérique on cyclic homology, among other places. 
Jul 20 
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A few questions about Kontsevich formality
Great answer :) 
Jul 17 
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How weird can Modular Tensor Categories be over nonalgebraically closed fields?
A recent result of Ehud Meir is that the Schur group constructed out of semisimple Hopf algebras is in fact the whole Brauer group, son one can get all CSAs if we allow for general Hopf algebras instead of just groups. 
Jul 13 
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What kind of algebra is the class of ordered pairs equipped with the binary operation which forms them?
Out of curiosity: is there an orderedpair definition which does not raise the rank? 
Jul 12 
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Why are we interested in the Fundamental Groupoid of a Space?
Have you searched in this site (and in math.stackexchange.com) for relevant questions and answers? I am sure this has been discussed before —in particular, by Ronnie Brown. 
Jul 11 
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(Krull) dimension of any associated graded ring of a ring R equals the dimension of R
@CSA, you can find en C&E or in Weibel or in many other places a construction of the ChevalleyEilenberg resolution of the trivial left module of an enveloping algebra. There is an analogue of that for bimodules. 
Jul 11 
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(Krull) dimension of any associated graded ring of a ring R equals the dimension of R
@CSA, that algebra is the enveloping algebra of the unique nonabelian Lie algebra of dimension 2. It's global dimension is equal to is bimodule projective dimension is equal to 2. 
Jul 11 
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(Krull) dimension of any associated graded ring of a ring R equals the dimension of R
@CSA, it is not true, so no :). For example, suppose $2\neq0$ in the field $k$; then the algebra $k[x]/(x^21)$ has zero dimension as a bimodule over itself, yet there is an increasing filtration on it such that the associated graded algebra is $k[x]/(x^2)$, which has infinite H dimension. In any case, there are several different things you can mean by «analogous»... 
Jul 10 
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When is separation of variables an acceptable assumption to solve a PDE?
But one rarely solves a PDE by separating variables in the boundary conditions: one usually finds eigensolutions and does a series development. 
Jul 8 
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A parametrization of subsets
Thanks! ${}{}{}$ 
Jul 8 
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Why localize spaces with respect to homology?
One old (I don't like the adverb cowardly...) construction of localizing modulo a functor is localization modulo torsion of abelian groups, à la Serre. 
Jul 8 
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Why localize spaces with respect to homology?
The localization at E is a description of what E sees: one has as much hope in it being useful as one trusts E to provide useful information, no? 
Jul 8 
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A parametrization of subsets
@JosephO'Rourke, yup! Thanks. 