bio | website | www2.imperial.ac.uk/~cdl10 |
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location | London | |
age | 26 | |
visits | member for | 3 years, 7 months |
seen | 4 hours ago | |
stats | profile views | 297 |
Oct 17 |
awarded | Yearling |
Oct 17 |
comment |
The topology on the Robba ring
Yes, I wondered about that but I don't think so. There will be elements of $\mathcal{R}_K$ for which that norm is not defined for any $r$, since we require convergence on some semi-open annulus $p^{-r}\leq t <1$ rather than the closed annulus $p^{-r}\leq t\leq 1$. |
Oct 17 |
asked | The topology on the Robba ring |
Jul 2 |
awarded | Curious |
Jul 1 |
asked | Complexes of arithmetic $\mathcal{D}$-modules with Frobenius structure |
Nov 8 |
awarded | Nice Question |
Nov 8 |
accepted | Pro-algebraic versus continuous Galois cohomology, and schematic homotopy types |
Nov 8 |
answered | Pro-algebraic versus continuous Galois cohomology, and schematic homotopy types |
Nov 7 |
revised |
Pro-algebraic versus continuous Galois cohomology, and schematic homotopy types
added 263 characters in body |
Nov 7 |
comment |
Pro-algebraic versus continuous Galois cohomology, and schematic homotopy types
No, I don't think so. By cohomology, I really mean $Hom_{D}(1,V[i])$, where $D$ is either of the triangulated categories, so $t$-structures don't come into it at all. I'll edit the question to make this clearer. |
Nov 6 |
revised |
Pro-algebraic versus continuous Galois cohomology, and schematic homotopy types
added 16 characters in body |
Nov 6 |
comment |
Pro-algebraic versus continuous Galois cohomology, and schematic homotopy types
Sorry, which particular section of the thesis did you have in mind? It seems to be talking about pro-finite homotopy types to me... |
Nov 5 |
asked | Pro-algebraic versus continuous Galois cohomology, and schematic homotopy types |
Oct 11 |
comment |
“Extended” Weil Cohomology Theories
Ah, I didn't know about Bloch-Ogus, that might be pretty much what I'm looking for. |
Oct 10 |
comment |
“Extended” Weil Cohomology Theories
No, their notion of a mixed Weil cohomology theory doesn't say anything about compact supports or Poincaré duality. It follows from their results that given a Weil cohomology theory, all the extra stuff pops out (by realising the motivic version), but it doesn't form part of their definition of a mixed Weil cohomology theory. |
Oct 10 |
asked | “Extended” Weil Cohomology Theories |
Oct 1 |
comment |
on a characterisation of regular D-modules
Are you sure? If we let $w=z^{-1}$, then the connection becomes $\nabla(f)=df+f\frac{dw}{w^2}$, so it doesn't have logarithmic poles around $w=0$. |
Sep 30 |
comment |
on a characterisation of regular D-modules
An easy way to see that there is no $\mathrm{Ext}^1$ on the de Rham side is to note that $M$ is rank one, i.e. invertible. We have the dual connection $M^{\vee}=(\mathcal{O}_X,\nabla^\vee)$ where $\nabla^\vee(f)=df+fdz$, and $M\otimes M^\vee$ is just the constant integrable connection $\mathcal{O}_X$. Hence we can pass between $\mathrm{Ext}_\nabla^1(M,M)$ and $\mathrm{Ext}_\nabla^1(\mathcal{O}_X,\mathcal{O}_X)$. |
Sep 30 |
answered | on a characterisation of regular D-modules |
Sep 16 |
awarded | Enthusiast |