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visits | member for | 4 years, 2 months |
seen | yesterday | |
stats | profile views | 2,208 |
It is great to learn math on this website.
Apr 28 |
awarded | Nice Question |
Apr 16 |
awarded | Great Question |
Mar 5 |
awarded | Yearling |
Mar 3 |
awarded | Notable Question |
Dec 2 |
awarded | Notable Question |
Nov 27 |
comment |
Intersections of hypersurfaces of degree $d$ in $\mathbb CP^n$
Thanks a lot for this! |
Nov 27 |
accepted | Intersections of hypersurfaces of degree $d$ in $\mathbb CP^n$ |
Nov 27 |
asked | Intersections of hypersurfaces of degree $d$ in $\mathbb CP^n$ |
Nov 8 |
awarded | Popular Question |
Sep 24 |
awarded | Autobiographer |
Jul 24 |
comment |
A topological criterion for connectedness of a semi-ample divisor
Artie, I think you right. Thank you! This reasoning is considerably simpler than what I had in mind. |
Jul 24 |
comment |
A topological criterion for connectedness of a semi-ample divisor
Artie, thanks for your comment. Why $f: X\to Y$ has connected fibres? |
Jul 24 |
revised |
A topological criterion for connectedness of a semi-ample divisor
added 10 characters in body |
Jul 24 |
asked | A topological criterion for connectedness of a semi-ample divisor |
Jul 22 |
comment |
Non-vanishing of elements in cohomology of full Flag varieties
I finally got it :) |
Jul 22 |
accepted | Non-vanishing of elements in cohomology of full Flag varieties |
Jul 21 |
comment |
Non-vanishing of elements in cohomology of full Flag varieties
Thank you very much David! I will need a bit of time to digest your proof :) |
Jul 21 |
comment |
Non-vanishing of elements in cohomology of full Flag varieties
abx, yes thank you, I understand (I added one more tag - combinatorics). I ask this question here because for the moment I can not answer this combinatorial question. |
Jul 21 |
revised |
Non-vanishing of elements in cohomology of full Flag varieties
edited tags |
Jul 21 |
comment |
Non-vanishing of elements in cohomology of full Flag varieties
No Peter, I am interested in classes $\sigma_i$. If one replaces $\sigma_i$ by $\sigma_i-\sigma_{i-1}$ as you suggest, the question becomes completely different (and easy to answer) |