Reputation
1,609
Top tag
Next privilege 2,000 Rep.
Edit questions and answers
Badges
1 14 19
Newest
 Yearling
Impact
~62k people reached

  • 0 posts edited
  • 0 helpful flags
  • 386 votes cast
Mar
7
comment When is the generalized Cantor space $\kappa$-compact?
Boaz: Yes, I was applying the tree property, but I see that the branch might be covered. And would only have worked for one implication anyway.
Mar
7
comment When is the generalized Cantor space $\kappa$-compact?
@Asaf: what about this argument by contradiction; for each $\alpha<\kappa$ the basic opens $[\sigma]$ with $\sigma \in 2^{\alpha}$ is an open covering of cardinality less than $\kappa$, so for at least one $\sigma$ the open $[\sigma]$ is not contained in the original open covering. Then by weak compactness there is a cofinal branch made of these $\sigma$'s which cannot be covered by the original open cover.
Feb
14
awarded  Yearling
Feb
5
comment A question about Borel sets on the unit interval
Yes, thanks. And thanks for the reference in your answer.
Feb
5
revised A question about Borel sets on the unit interval
added 6 characters in body
Feb
5
accepted A question about Borel sets on the unit interval
Feb
5
asked A question about Borel sets on the unit interval
Jan
26
accepted Why hasn't mereology succeeded as an alternative to set theory?
Jan
26
comment Why hasn't mereology succeeded as an alternative to set theory?
That a decidable theory cannot be foundational is a beautiful argument. It reveals the richness one gets from incompleteness.
Jul
18
comment riemann mapping theorem for skew-fields of quaternions and beyond
Please check the following paper on the subject: C.A. Deavours (1973) "The Quaternion Calculus", American Mathematical Monthly 80:995–1008.
Apr
12
awarded  Enlightened
Apr
12
awarded  Nice Answer
Feb
14
awarded  Yearling
Jan
12
comment A question regarding the Hahn-Banach theorem
It's clear that such a measure must take values within $0$ and $1$, but in order to even state countable additivity you would need $B$ to have countable joins and meets, which is not necessarily going to happen. Regarding $WKL_0$, you need to specify which base theory and which statement of Hahn-Banach theorem you are considering. $ZF$ is too strong since it proves Weak König's lemma, and the general formulation of Hahn-Banach theorem as in the above equivalence involves arbitrary vector spaces not necessarily definable in second order arithmetic.
Jan
9
answered A question regarding the Hahn-Banach theorem
Dec
7
comment What are the current views on consistency of Reinhardt cardinals without AC?
...But it is conceivable that a large cardinal hierarchy could be mirrored in an intuitionistic setting where more notions of large cardinals can be defined without inconsistency (they will have to be non-classical though).
Dec
7
comment What are the current views on consistency of Reinhardt cardinals without AC?
This is just speculative, but even if some large cardinals are found to be inconsistent with ZF, there could be weaker set theories where appropriate versions are consistent. I'm thinking more precisely of Aczel's constructive set theory CZF, based on intuitionistic logic, over which appropriate notions of regular, inaccessible and even Mahlo cardinals are defined (see "Inaccessibility in constructive set theories and type theories" by Rathjen-Griffor-Palmgren). In this case, the addition of AC turns the theory in just ZFC plus the usual notions...(cont.)
Dec
6
comment $\zeta(0)$ and the cotangent function
Given the fact that what you end up explaining why the series, considered as a Laurent series, predicts also the values of $\zeta$ at the negative even numbers, I think this proof is as simple as it reasonably can be expected to be. This because you are forced to consider the analytic continuation of $\zeta$ to the left half plane, not just to the critical strip, so it's reasonable that the functional equation is invoked.
Nov
5
comment Mysterious quotes (at least for me)
There is a very particular way in which those quotes make sense to me, but I'm afraid is not a mathematical way so I can't really answer :)
Oct
16
revised Is it possible to formulate the axiom of choice as the existence of a survival strategy?
added 1981 characters in body