bio | website | |
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location | ||
age | 33 | |
visits | member for | 3 years, 8 months |
seen | Sep 18 at 20:26 | |
stats | profile views | 425 |
Right now, I'm a math grad student at the University of Miami.
Sep 24 |
awarded | Autobiographer |
Sep 11 |
comment |
In what sense is the classification of all finite groups “impossible”?
I had the arxiv link in mind. |
Sep 10 |
comment |
In what sense is the classification of all finite groups “impossible”?
1. Can we make that expository paper about wild linear algebra problems community wiki? 2. Speaking of wildness and computational complexity, how do those problems behave when the field of interest is finite? Simultaneous conjugacy of ordered pairs of matrices is, for example, obviously in NP. |
Sep 6 |
comment |
What are smallest finite images of triangle groups?
It is worth noting that there are finite simple groups whose simplicity cannot be proved this way. Since the $(2,3,5)$ triangle group is isomorphic to $A_{5}$, $A_{6}$ and $PSU_{4}(2)$ cannot be proven simple this way. I am not sure if there are any other examples. |
Jul 7 |
answered | Variations to Cayley's Embedding Theorem for Groups |
Jul 6 |
accepted | Subgroup property stronger than being characteristic |
Jul 3 |
revised |
Subgroup property stronger than being characteristic
"without having" --> "instead of having" because "< |
Jul 3 |
answered | Fantastic properties of Z/2Z |
Jul 3 |
comment |
Subgroup property stronger than being characteristic
Geoff, I am impressed by the nontrivial extent to which you read my mind -- I did not know the Thompson subgroup always did this, but I was trying to get a better handle on some local analysis. |
Jul 2 |
asked | Subgroup property stronger than being characteristic |
Jul 2 |
awarded | Curious |
Jun 20 |
awarded | Popular Question |
May 27 |
awarded | Enlightened |
May 27 |
awarded | Nice Answer |
May 1 |
comment |
Non-trivial consequences of Baer's theorem and Lucchini's theorem in subnormality theory
A nice consequence I've encountered of the Baer-Suzuki theorem: |
Apr 24 |
answered | Results about the existence of solutions in groups |
Apr 17 |
answered | Variations to Cayley's Embedding Theorem for Groups |
Apr 8 |
comment |
Conjugation Quandles and… “Quandle-Groups”? From quandles to Groups
I am not sure how well this pans out, but the natural group to start working from would be the subgroup of $S_{|Q|}$ generated by actions of elements of $Q$ on $Q$. |
Mar 5 |
awarded | Nice Question |
Feb 3 |
awarded | Necromancer |