Hugo Chapdelaine

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 Name Hugo Chapdelaine Member for 2 years Seen 5 hours ago Website Location Quebec city Age 35
 Mar27 comment non-trivial topological line bundles over cartesian product of manifolds not coming from a pullback Ok, I was being idiot Mar27 comment non-trivial topological line bundles over cartesian product of manifolds not coming from a pullback I see, so this explains why I was not able to construct such an example. What about complex line bundle? Mar27 revised non-trivial topological line bundles over cartesian product of manifolds not coming from a pullback added 90 characters in body; added 52 characters in body Mar27 comment non-trivial topological line bundles over cartesian product of manifolds not coming from a pullback Yes, I forgot to mention that I don't want $L$ to be coming from the pullback of a line bundle over $Y$. Mar27 asked non-trivial topological line bundles over cartesian product of manifolds not coming from a pullback Mar23 comment Generalizing the square theoremthanks for the reference! Mar22 comment Generalizing the square theoremHi @Angelo, thanks for the example. I never played with reflexive $\mathcal{O}_X$-modules. They seem to enjoy nice properties like $j_*G=F$. Do you have a reference for this last property? Mar20 asked Generalizing the square theorem Mar13 asked On the square theorem for commutative algebraic groups Mar6 awarded ● Popular Question Jan31 comment On Weil’s characters of type (A)Thanks a lot Keerthi! Your proof seems to be correct. Jan31 comment On Weil’s characters of type (A)Hi Keerthi, I'm confused about one point. If $Stab(f)=H\leq G_{\mathbf{Q}}$, then you are showing that for all complex conjugation $c\in G_{\mathbf{Q}}$, $cHc^{-1}=H$. But this does not seem to imply that $L:=\bar{\mathbf{Q}}^{H}$ is a CM field. For example, if $L$ is Galois over $\mathbf{Q}$ and not CM, then the condition $cHc^{-1}=H$ is trivially satisfied since $H$ is normal in $G_{\mathbf{Q}}$. Am I right? Jan31 revised On Weil’s characters of type (A)edited body Jan30 asked On Weil’s characters of type (A) Jan29 awarded ● Popular Question Jan18 revised The normalizer a maximal compact subgroup of a semi-simple Lie groupadded 104 characters in body Jan18 revised The normalizer a maximal compact subgroup of a semi-simple Lie groupadded 30 characters in body Jan18 asked The normalizer a maximal compact subgroup of a semi-simple Lie group Dec22 awarded ● Yearling Nov27 awarded ● Popular Question