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visits member for 5 years, 2 months
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I am currently a NSERC postdoctoral fellow at Stony Brook University.


Dec
12
comment Bound areas of disks with respect to a quadratic differential
@DylanThurston : I'm glad I could help.
Dec
12
revised Bound areas of disks with respect to a quadratic differential
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Dec
12
revised Bound areas of disks with respect to a quadratic differential
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Dec
12
comment Bound areas of disks with respect to a quadratic differential
Yes, I made a silly mistake. I corrected my answer, hopefully it works now.
Dec
12
revised Bound areas of disks with respect to a quadratic differential
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Dec
12
answered Bound areas of disks with respect to a quadratic differential
Dec
8
accepted Is this infinite series related to some well-known special functions?
Dec
8
comment Is this infinite series related to some well-known special functions?
Great, thank you! +1
Dec
8
awarded  Good Answer
Dec
4
comment Starshapeness of polynomial tracts with respect to the (entire collection of) critical points contained in the tract
Do you assume that $G$ is connected?
Dec
3
comment Starshapeness of polynomial tracts with respect to the (entire collection of) critical points contained in the tract
There is also a simple proof using potential theory in the book "Potential theory in the complex plane" by Thomas Ransford, Theorem 5.5.8. I don't have access to Walsh's book right now, so I don't know if the proof is the same.
Nov
14
comment Applications of the Small and Great Theorems of Picard
@GHfromMO Ah, I didn't realize you were talking about meromorphic functions. Good point! The argument works for entire functions, but I don't know how to prove the result for meromorphic functions using Picard's theorem.
Nov
14
comment Applications of the Small and Great Theorems of Picard
@GHfromMO : From the factorization $1=\prod_{j=1}^n (f-\zeta_j g)$ where $\zeta_1,\dots,\zeta_n$ are the $n$ roots of $z^n+1=0$, it follows that $f/g$ is a meromorphic function that omits the values $\zeta_1,\dots,\zeta_n$, and hence must be constant by Picard's theorem. From this it follows easily that both $f$ and $g$ must be constant.
Nov
12
comment Non-trivial global solution for Dirichlet eigenvalue problem
I don't understand the new formulation... If $\Delta f = \lambda f$ almost everywhere, then $\Delta f = \lambda f$ everywhere just by continuity.
Nov
5
comment Is this infinite series related to some well-known special functions?
The formula looks correct, but I have no idea how to obtain it...
Nov
5
comment Is this infinite series related to some well-known special functions?
Whoa, where does that come from? :-)
Nov
5
revised Is this infinite series related to some well-known special functions?
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Nov
5
comment Is this infinite series related to some well-known special functions?
@NateEldredge I tried with Maple and didn't get anything, but it might just mean I don't know how to use Maple properly!
Nov
5
asked Is this infinite series related to some well-known special functions?
Oct
17
awarded  Good Answer