bio | website | sites.google.com/site/… |
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location | Québec | |
age | ||
visits | member for | 5 years, 2 months |
seen | 4 hours ago | |
stats | profile views | 1,883 |
I am currently a NSERC postdoctoral fellow at Stony Brook University.
Dec 12 |
comment |
Bound areas of disks with respect to a quadratic differential
@DylanThurston : I'm glad I could help. |
Dec 12 |
revised |
Bound areas of disks with respect to a quadratic differential
added 67 characters in body |
Dec 12 |
revised |
Bound areas of disks with respect to a quadratic differential
deleted 25 characters in body |
Dec 12 |
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Bound areas of disks with respect to a quadratic differential
Yes, I made a silly mistake. I corrected my answer, hopefully it works now. |
Dec 12 |
revised |
Bound areas of disks with respect to a quadratic differential
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Dec 12 |
answered | Bound areas of disks with respect to a quadratic differential |
Dec 8 |
accepted | Is this infinite series related to some well-known special functions? |
Dec 8 |
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Is this infinite series related to some well-known special functions?
Great, thank you! +1 |
Dec 8 |
awarded | Good Answer |
Dec 4 |
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Starshapeness of polynomial tracts with respect to the (entire collection of) critical points contained in the tract
Do you assume that $G$ is connected? |
Dec 3 |
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Starshapeness of polynomial tracts with respect to the (entire collection of) critical points contained in the tract
There is also a simple proof using potential theory in the book "Potential theory in the complex plane" by Thomas Ransford, Theorem 5.5.8. I don't have access to Walsh's book right now, so I don't know if the proof is the same. |
Nov 14 |
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Applications of the Small and Great Theorems of Picard
@GHfromMO Ah, I didn't realize you were talking about meromorphic functions. Good point! The argument works for entire functions, but I don't know how to prove the result for meromorphic functions using Picard's theorem. |
Nov 14 |
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Applications of the Small and Great Theorems of Picard
@GHfromMO : From the factorization $1=\prod_{j=1}^n (f-\zeta_j g)$ where $\zeta_1,\dots,\zeta_n$ are the $n$ roots of $z^n+1=0$, it follows that $f/g$ is a meromorphic function that omits the values $\zeta_1,\dots,\zeta_n$, and hence must be constant by Picard's theorem. From this it follows easily that both $f$ and $g$ must be constant. |
Nov 12 |
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Non-trivial global solution for Dirichlet eigenvalue problem
I don't understand the new formulation... If $\Delta f = \lambda f$ almost everywhere, then $\Delta f = \lambda f$ everywhere just by continuity. |
Nov 5 |
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Is this infinite series related to some well-known special functions?
The formula looks correct, but I have no idea how to obtain it... |
Nov 5 |
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Is this infinite series related to some well-known special functions?
Whoa, where does that come from? :-) |
Nov 5 |
revised |
Is this infinite series related to some well-known special functions?
added 292 characters in body |
Nov 5 |
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Is this infinite series related to some well-known special functions?
@NateEldredge I tried with Maple and didn't get anything, but it might just mean I don't know how to use Maple properly! |
Nov 5 |
asked | Is this infinite series related to some well-known special functions? |
Oct 17 |
awarded | Good Answer |