bio | website | chemie.uni-hamburg.de/ac/AKs/… |
---|---|---|
location | Hamburg | |
age | 53 | |
visits | member for | 3 years, 4 months |
seen | yesterday | |
stats | profile views | 1,141 |
knot theory dilettant!
Apr 7 |
asked | “Mutant knots” generalizable to “mutant tangled graphs”? |
Feb 28 |
comment |
(Graded) Lie algebras with “nice” irreps
Ah, I see. This is a newer version of the paper with added sextonions (and a few more graded Lie algebras therein). Everything lies on the Vogel plane but THX. |
Feb 26 |
asked | (Graded) Lie algebras with “nice” irreps |
Feb 26 |
comment |
Replacing the Lie commutator with something else
@UwF and arsmath: Bingo! THX for the references. (I knew it existed, but I wouldn't have known where to begin searching.) |
Feb 24 |
revised |
Replacing the Lie commutator with something else
If it's still unclear, feel free to delete without asking. |
Feb 21 |
asked | Replacing the Lie commutator with something else |
Jan 31 |
asked | “Unicolor” irreps (R is in RxR) |
Jan 28 |
accepted | Generalizations of Lie algebras |
Jan 27 |
asked | Generalizations of Lie algebras |
Dec 30 |
revised |
Commutators for quantum Lie algebras
Added pic with the formula I'm seeking, but it's just a wild guess. |
Dec 28 |
asked | Commutators for quantum Lie algebras |
Dec 18 |
comment |
Minimal set of 2-2 Pachner move null sequences on a (nonplanar) trivalent graph?
Well, if I could prove that you only have to consider moves on adjacent nodes, it would be easy. Let A flip nodes 1 and 2, B (23) and C (34). AC=CA, but I still can't reduce, say, ABCABC, since already the naming here is inconsistent - after I did move A, 1 and 2 aren't 1 and 2 anymore... |
Dec 17 |
revised |
Minimal set of 2-2 Pachner move null sequences on a (nonplanar) trivalent graph?
Now with pic |
Dec 16 |
asked | Minimal set of 2-2 Pachner move null sequences on a (nonplanar) trivalent graph? |
Dec 11 |
awarded | Yearling |
Oct 21 |
asked | Use of “abstract tensors” for trivalent graphs |
Sep 18 |
comment |
Matrix power problem
@anyone who stumbles over this: It seems (I experimented with MATHEMATICA's NSOLVE command) that if S and D are given, B is uniquely (apart from signs and complex conjugates) defined. Of course I can't prove it. |
Sep 12 |
comment |
Matrix power problem
@Gerry - your question is very justified in the general case, where no variables are known at all (and where I express B in terms of S elements - that's the best I can do). J and D are mostly irrelevant to this question (except they restrict the form of B somewhat). In this special case, I usually solve for B for any sign combination of S. |
Sep 11 |
asked | Matrix power problem |
Aug 14 |
accepted | Are all commuting functions “the same”? |