Carlo Beenakker

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Name Carlo Beenakker
Member for 2 years
Seen 4 hours ago
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Location Leiden, The Netherlands
Age
physicist at Leiden University
1d
comment How can I randomly draw an ensemble of unit vectors that sum to zero?
@Allen, wouldn't the rescaling to unit length spoil the sum to zero?
2d
comment Derivation of Bessel functions
yes, $u\ll 1$ means that the quadratic (convective) terms are neglected; and indeed, the Bessel equation, which has Bessel functions as solutions, is a linear equation, so it cannot include the convective term; see my full answer below.
2d
revised The relations between the Perelman’s entropy functional and notions of entropy from statistical mechanics
Perelman quote
2d
revised The relations between the Perelman’s entropy functional and notions of entropy from statistical mechanics
rewording
2d
answered The relations between the Perelman’s entropy functional and notions of entropy from statistical mechanics
2d
comment The relations between the Perelman’s entropy functional and notions of entropy from statistical mechanics
it seems to be little more than a formal correspondence, judging from page 11 of arxiv.org/abs/math.DG/0211159
2d
revised Derivation of Bessel functions
p_0
2d
answered Derivation of Bessel functions
2d
comment Derivation of Bessel functions
as far as I can see, the solution you have written down for the density $\rho$ neglects the nonlinear term $u\cdot\nabla u$, so any effect of convection is neglected and it only applies in the limit of small velocities $u$; in that limit, indeed, the differential equation for $\rho$ is just the Poisson equation, which in cylindrical coordinates has the Bessel function solution; all the complications of hydrodynamics (shock waves, turbulence, etc.) come from the nonlinear convective term $u\cdot\nabla u$ which is neglected; once you add that term, there is no closed form solution.
May
17
comment how to proof this Stirling related equation
sorry, I misunderstood the left and right hand side both as fractions, my mistake
May
17
comment Series expansion with remaining $log n$
the series expansion is easiest if you first take the logarithm, and then you find directly a powerseries in $n^{-1}\ln n$, $$-\frac{k(k+1)}{2n}\ln n+2\ln(2kn)\left[\sum_{p=0}^{\infty}\frac{1}{p}k^p(1+k)^p(2kn)^{-p}(\ln n)^p \right]$$
May
17
comment How to maximize the determinant of a matrix of the form VDV^H
thank you, Federico, I stand corrected; the correct formula is $${\rm Det}A=\sum_{S}|{\rm Det}V_{S}|^2\prod_{k\in S}D_{kk}$$ where $S$ is a subset of $M$ indices out of $1,2,...2M$ and $V_S$ is an $M\times M$ matrix constructed from $V$ by deleting the $M$ columns that are not in $S$. it would seem that to maximize this is in general not trivial.
May
17
comment how to proof this Stirling related equation
the left hand side is infinite, so the inequality is obviously false.
May
17
comment How to maximize the determinant of a matrix of the form VDV^H
since $Det A = (Det V^H V) \prod_n D_n$, this is trivial
May
16
revised computing Bernoulli numbers
zeta function
May
16
answered computing Bernoulli numbers
May
15
answered help on antiderivative of a vector function
May
15
comment help on antiderivative of a vector function
hmm, votes to close .... is it trivial?
May
15
accepted Principal value of integral
May
15
revised Eigenvalues of random Hamiltonian matrices
added reference
May
14
comment Principal value of integral
I added several more intermediate steps; is it clear now?
May
14
revised Principal value of integral
math corrected
May
14
revised Principal value of integral
explanation
May
14
revised Principal value of integral
derivation
May
14
comment Principal value of integral
the integral can be done as a contour integral in the complex plane, using the definition of principal value which I gave in a comment to your question above (so as the average of a contour closed in the upper and lower half of the complex plane, once picking up the pole at $x=i\epsilon$ and once at $x=-i\epsilon$; I will try to add this calculation to my answer later today.
May
14
comment Principal value of integral
@Gerald: it is equivalent to the textbook definition ${\cal P}\int_a^b dx f(x)=\frac{1}{2} \lim_{\epsilon\rightarrow 0}\left(\int_{a-i\epsilon}^{b-i\epsilon} dx f(x)+ \int_{a+i\epsilon}^{b+i\epsilon} dx f(x)\right)$
May
14
revised Principal value of integral
typo
May
14
answered Principal value of integral
May
14
comment Principal value of integral
I would presume each pole at $x_n=n\pi$ is excluded in an interval $(x_n-\epsilon,x_n+\epsilon)$, and then the limit $\epsilon\rightarrow 0$ is taken.
May
13
comment Eigenvalues of random Hamiltonian matrices
no, we checked numerically that the eigenvalue density vanishes linearly with the distance from either real or imaginary axis; moreover, there is a linear repulsion of pairs of eigenvalues on the real axis, as well as on the imaginary axis; in these respects the Hamiltonian ensemble behaves just like the Ginibre ensemble.
May
13
accepted Eigenvalues of random Hamiltonian matrices
May
13
comment Analytical continuation of electrostatic potentials
since your charge density solves the Poisson equation, your potential has the Fourier representation $V(\vec{r})\propto\int d\vec{k} \exp(i\vec{k}\cdot\vec{r})k^{-2}\rho_{C}(\vec{k})$. So you see that if the Fourier transformed charge density $\rho_C(\vec{k})$ decays only as a power law in $k$, then the potential must diverge exponentially for any imaginary $\vec{r}$. This seems unavoidable.
May
13
comment Eigenvalues of random Hamiltonian matrices
@Federico: you're completely correct, I did not properly define the limit in which the density becomes uniform; I've corrected that now; the uniformity applies to the rescaled density; the nonuniformities in the rescaled density are of order $n^{1/2}$, so the factor $n^{-1}$ removes them in the large−$n$ limit.
May
13
revised Eigenvalues of random Hamiltonian matrices
rescaling
May
13
comment Eigenvalues of random Hamiltonian matrices
thank you for asking: this is certainly not an artifact; in the Ginibre ensemble the eigenvalue density is known to vanish linearly on approaching the real axis; basically the depletion zone signals the accumulation of eigenvalues on the real axis, as if the eigenvalues are "attracted" towards the real axis, where they condense. It seems that the repulsion from the imaginary axis is stronger than linear, but this is something we have not yet checked.
May
13
revised Eigenvalues of random Hamiltonian matrices
typo
May
13
answered Eigenvalues of random Hamiltonian matrices
May
11
comment A problem about Joint sine and cosine fourier transform
hmm, there is no square root in the denominator? if there was a square root, then we could define $\alpha=\arccos(\lambda/\sqrt{\lambda^2+h^2})$ and your kernel would simply be $K(x,\lambda)=\sqrt{2/\pi}\cos(\lambda x-\alpha)$
May
11
revised Lower bounds on derivative around zero set of a positive smooth function.
small edit
May
11
revised Lower bounds on derivative around zero set of a positive smooth function.
simpler
May
11
revised Lower bounds on derivative around zero set of a positive smooth function.
one more step
May
11
answered Lower bounds on derivative around zero set of a positive smooth function.
May
9
comment Prove that the sum of a certain infinite series is 1
can you give some background how this identity to unity arises? does that suggest a way to a proof?
May
8
accepted Probability distribution for two-state system that depends on residence time
May
8
revised Probability distribution for two-state system that depends on residence time
remove header
May
8
comment Probability distribution for two-state system that depends on residence time
@ionlet: I expanded the answer, hopefully answering all your queries; is it clear now?
May
8
revised Probability distribution for two-state system that depends on residence time
expanded
May
8
revised Probability distribution for two-state system that depends on residence time
corrected
May
7
answered Probability distribution for two-state system that depends on residence time
May
5
accepted Non-asymptotic results for bulk of random Wishart matrix