Steven Gubkin

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Name Steven Gubkin
Member for 3 years
Seen 6 hours ago
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Location Columbus, Ohio
Age 25
I am a grad student with a wide base of interests, but my main focus now is on complex analysis and elementary mathematics education.
17h
awarded  Nice Question
May
21
comment Why do knot cobordisms result in functoriality with respect to knot homologies so often?
I think Neil is saying you should have some more backround information. Can you give some examples of this phenomenon? How did it arise in your work? You say often - can you explain some situations where it fails, and give your thoughts on how these situations are different?
May
17
comment Is there any proof that you feel you do not “understand”?
@Dustin: That is great!
May
17
comment Is there any proof that you feel you do not “understand”?
This proof does not seem to "clever" to me. Seems like a natural thing someone might realize if they were given 4 congrunent triangles to play with. takayaiwamoto.com/Pythagorean_Theorem/…
May
17
comment Is there any proof that you feel you do not “understand”?
I feel like I made a big breakthrough in my understanding of the fundamental theorem once I realized that when you use Euler's method on y'=f(x) given y(a)=0 and try to find y(b), the expression given by Euler's method is the riemann sum for the definite integral of f(x) from a to b. This shows why finding antiderivatives is linked to definite integration for me.
May
17
answered Is there any proof that you feel you do not “understand”?
Mar
5
awarded  Good Question
Feb
21
awarded  Good Answer
Feb
18
comment Another proof of the bidisc and the ball are biholomorphically inequivalent?
Thanks - this is really great. Do you have a reference for this? It doesn't directly address the curvature question. I am still reasonably convinced that I didn't goof too badly in my computation, and the the sectional curvatures alone distinguish the two spaces.
Feb
18
comment Another proof of the bidisc and the ball are biholomorphically inequivalent?
IIRC this result is only true for smoothly bounded domains, so it does not apply to the bidisc. Isn't the holomorphic sectional curvature of the bidisc also constant?
Feb
11
awarded  Popular Question
Jan
30
asked Another proof of the bidisc and the ball are biholomorphically inequivalent?
Nov
29
awarded  Nice Answer
Nov
29
answered Integrating Powers without much Calculus
Nov
29
comment Integrating Powers without much Calculus
This is very clever, and I like it a lot, but I still feel that investigating this small sliver of area is essentially reproving the fundamental theorem of calculus in this special case.