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Dec
27 |
comment |
Numerical invariants of symmetric products of curves
Thank you for the very nice answer! |
Dec
27 |
accepted | Numerical invariants of symmetric products of curves |
Dec
26 |
comment |
Numerical invariants of symmetric products of curves
I am interested in $n<g$. |
Dec
26 |
revised |
Numerical invariants of symmetric products of curves
edited body |
Dec
26 |
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Numerical invariants of symmetric products of curves
@JasonStarr: thank you. In fact $C$ general is what I am interested in, and $g$ large with respect to $n$ is also fine. |
Dec
26 |
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Numerical invariants of symmetric products of curves
yes, I mean nef&big canonical bundle |
Dec
26 |
asked | Numerical invariants of symmetric products of curves |
Nov
6 |
awarded | Yearling |
May
12 |
awarded | Nice Answer |
Dec
7 |
awarded | Custodian |
Dec
7 |
reviewed | Approve Definition of an E-infinity algebra |
Nov
8 |
answered | Kummer Coverings |
Nov
6 |
awarded | Yearling |
Sep
24 |
awarded | Autobiographer |
Jul
8 |
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smooth quotient out of a singular variety?
I forgot irreducible, sorry! |
Jul
8 |
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smooth quotient out of a singular variety?
A variation of this answer in order to satisfy Libli's request that the example be quasi-projective: take $X$ the union of two planes of $\mathbb C^4$ intersecting at the origin and let $\mathbb Z_2$ act by identifying the two planes via any linear isomorphism. $X$ is affine and behaves as Dan's example. |
Jul
2 |
awarded | Curious |
Jun
28 |
awarded | Popular Question |
Mar
4 |
comment |
Does $h^1(D)=0$ imply numerical connectedness on K3 surfaces?
Ciao Pigna! welcome to MO! |
Mar
4 |
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Does $h^1(D)=0$ imply numerical connectedness on K3 surfaces?
No. For instance if $A$ is a a rational curve with $A^2<0$, then $h^0(\mathcal O_A(-A))>0$. |