bio | website | |
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location | ||
age | ||
visits | member for | 4 years, 2 months |
seen | Dec 15 '14 at 20:10 | |
stats | profile views | 290 |
Jul 11 |
asked | Density of p-ordinary modular forms |
Jul 2 |
awarded | Curious |
Apr 15 |
accepted | Algebra and Cancer Research |
Apr 15 |
awarded | Popular Question |
Apr 14 |
awarded | Nice Question |
Apr 14 |
awarded | Yearling |
Apr 14 |
comment |
Algebra and Cancer Research
This is excellent! |
Apr 14 |
comment |
Algebra and Cancer Research
This is exactly the sort of thing I'm looking for. Thank you! |
Apr 14 |
comment |
Algebra and Cancer Research
@PerAlexandersson That sounds interesting. Can you give a reference for further reading? Thanks! |
Apr 14 |
asked | Algebra and Cancer Research |
Feb 21 |
awarded | Necromancer |
Feb 21 |
revised |
Elliptic curves over $\mathbb{Q}$ with no rational torsion and $\mu$-invariant equal to 1 at $p=3$
added 122 characters in body |
Feb 21 |
comment |
Elliptic curves over $\mathbb{Q}$ with no rational torsion and $\mu$-invariant equal to 1 at $p=3$
I see now...my mistake! Anyway, this would still be my suggested approach... |
Feb 21 |
comment |
Elliptic curves over $\mathbb{Q}$ with no rational torsion and $\mu$-invariant equal to 1 at $p=3$
Pollack's table claims that $\mu=1$ at $p=3$. |
Feb 21 |
answered | Elliptic curves over $\mathbb{Q}$ with no rational torsion and $\mu$-invariant equal to 1 at $p=3$ |
Jan 9 |
comment |
Are the Fourier coefficients of a new form real
The reference for this is Proposition 3.2 of Ken Ribet's "Galois Representations Attached to Eigenforms with Nebentypus". |
Oct 5 |
awarded | Civic Duty |
Sep 7 |
accepted | Periods of Twists of Modular Forms |
Sep 7 |
asked | Periods of Twists of Modular Forms |
Jul 3 |
comment |
Hecke Characters
Ah, yes, those notes are dealing in a much more general setting (automorphic representations) than the one you care about (elliptic curves). Sorry about that. I don't have time to write something myself at the moment, and in any case, there are people here much more qualified than me to do so. I'm sorry that link wasn't more helpful! |