John R Ramsden

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Name	John R Ramsden
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Does $(x^2 - 1)(y^2 - 1) = c z^4$ have a rational point, with z non-zero, for any given rational c?

may 23 12 at 2:01 Noam D. Elkies 18.1k●4●63●91

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184

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Rational solutions of $x (y - z) y (z - x) z (x - y) = t^2$

ag.algebraic-geometry nt.number-theory

jul 28 at 22:46 John R Ramsden 579●2●10

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245

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Rank of $x (x^2 - 1) = c (c^2 - 1) y^2 $ over $\mathbb{Q}$ for given rational values of $c$

nt.number-theory elliptic-curves ag.algebraic-geometry

jun 18 at 1:08 Joseph O'Rourke 43.4k●1●50●214

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292

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Looking up the Mordell-Weil rank and generator(s) of a Weierstrass Equation

ag.algebraic-geometry nt.number-theory

mar 5 11 at 23:10 Esteban Crespi 353●2●8

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299

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The surface $ x^2 y^2 + 1 = (x^2 + y^2) z^2 $

diophantine-equations k3-surfaces

jan 2 11 at 13:49 John R Ramsden 579●2●10

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449

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The variety $x_1 + x_2 + .. + x_n = 0$, $x_1 x_2 .. x_n = 1$ for n > 4

ag.algebraic-geometry

jan 14 12 at 13:42 John R Ramsden 579●2●10

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271

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Numerical method for finding characteristics of a square wave

na.numerical-analysis

jul 7 at 1:22 MathOverflow♦ 1●2●3

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103

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Dually automorphic varieties

ag.algebraic-geometry

may 29 at 22:21 François G. Dorais♦ 22.7k●2●49●114

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Not especially famous, long-open problems which anyone can understand

Examples of common false beliefs in mathematics. (2)

Does $(x^2 - 1)(y^2 - 1) = c z^4$ have a rational point, with z non-zero, for any given rational c?

Analysis of a quadratic diophantine equation

Diophantine Equation with Polynomial Coefficients

Reference request: an elementary proof of Brouwer fixed-point theorem.

Does this surface contain all perfect cuboids?

Which Diophantine equations can be solved using continued fractions?

Omniscient bots gathering on $\mathbb{Z}^2$

The variety $x_1 + x_2 + .. + x_n = 0$, $x_1 x_2 .. x_n = 1$ for n > 4

Impossible Heronian Triangles (Ratio of 2 Sides)

Are nontrivial integer solutions known for $x^3+y^3+z^3=3$?

Fiction books about mathematicians?

Parametrization of the intersection of an ellipsoid with a sphere

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Questions

Does $(x^2 - 1)(y^2 - 1) = c z^4$ have a rational point, with z non-zero, for any given rational c?

Rational solutions of $x (y - z) y (z - x) z (x - y) = t^2$

Rank of $x (x^2 - 1) = c (c^2 - 1) y^2 $ over $\mathbb{Q}$ for given rational values of $c$

Looking up the Mordell-Weil rank and generator(s) of a Weierstrass Equation

The surface $ x^2 y^2 + 1 = (x^2 + y^2) z^2 $

The variety $x_1 + x_2 + .. + x_n = 0$, $x_1 x_2 .. x_n = 1$ for n > 4

Numerical method for finding characteristics of a square wave

Dually automorphic varieties

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