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7
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edited Jan 3 2010 at 10:22
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Let $k$ be a finite field of characteristic $p$. There is only one
characteristic-$p$ local field with residue field $k$, namely
$k((\pi))$, where $\pi$ is transcendental, and there is a "smallest"
characteristic-$0$ local field with residue field $k$, namely the
degree-$a$ unramified extension $K$ of $\mathbb{Q}_p$, where $q=p^a$ is
the cardinality of $k$.
Every characteristic-$0$ local field with residue field $k$ is a
finite totally ramified extension of $K$, and every finite totally
ramified extension of $K$ has residue field $k$.
As $K$ has only finitely many extensions of any given degree, we might
ask for the number of totally ramified extensions $L|K$ of given
degree $[L:K]=n$. Serre's "mass formula" (Comptes rendus 1978),
says that there are exactly $n$ such extensions, when counted
properly. This formula was also proved by Krasner by his methods.
Let Serre explain:
"Let $K$ be a local field, with finite residue
field with $q$ elements. Let $n$ be a positive integer, and let
$\Sigma_n$ be the set of all totally ramified extensions of $K$ of
degree $n$ contained in a given separable closure of $K$. If
$(n,p)=1$, \operatorname{gcd}(n,p)=1$, it is easy to show that $\text{Card}(\Sigma_n)=n$. If $L$
belongs to $\Sigma_n$, put $c(L)=d(L)-n+1$, where $d(L)$ is the
valuation of the discriminant of $L/K$. Our 'mass formula' is
$\sum_{L\in \Sigma_n} q^{-c(L)}=n$.
We give two proofs. The first one
uses Eisenstein polynomials, while the second one applies the H. Weyl
integration formula to the multiplicative group of a division
algebra." MR0500361 (80a:12018)
(Note that $k((\pi))$ has many totally ramified extensions $L$, but they are all of the form $L=k((\varpi))$ for some uniformiser $\varpi$ of $L$.)
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6
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edited Dec 27 2009 at 5:51
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Let $k$ be a finite field of characteristic $p$. There is only one
characteristic-$p$ local field with residue field $k$, namely
$k((\pi))$, where $\pi$ is transcendental, and there is a "smallest"
characteristic-$0$ local field with residue field $k$, namely the
degree-$a$ unramified extension $K$ of $\mathbb{Q}_p$, where $q=p^a$ is
the cardinality of $k$.
Every characteristic-$0$ local field with residue field $k$ is a
finite totally ramified extension of $K$, and every finite totally
ramified extension of $K$ has residue field $k$.
As $K$ has only finitely many extensions of any given degree, we might
ask for the number of totally ramified extensions $L|K$ of given
degree $[L:K]=n$. Serre's "mass formula" (Comptes rendus 1978),
says that there are exactly $n$ such extensions, when counted
properly. This formula was also proved by Krasner by his methods.
Let Serre explain:
"Let $K$ be a local field, with finite residue
field with $q$ elements. Let $n$ be a positive integer, and let
$\Sigma_n$ be the set of all totally ramified extensions of $K$ of
degree $n$ contained in a given separable closure of $K$. If
$(n,p)=1$, it is easy to show that $\text{Card}(\Sigma_n)=n$. If $L$
belongs to $\Sigma_n$, put $c(L)=d(L)-n+1$, where $d(L)$ is the
valuation of the discriminant of $L/K$. Our 'mass formula' is
$\sum_{L\in \Sigma_n} q^{-c(L)}=n$.
We give two proofs. The first one
uses Eisenstein polynomials, while the second one applies the H. Weyl
integration formula to the multiplicative group of a division
algebra." MR0500361 (80a:12018)
(Note that $k((\pi))$ has many totally ramified extensions $L$, but they are all of the form $L=k((\varpi))$ for some uniformiser $\varpi$ of $L$.)
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5
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edited Dec 27 2009 at 5:39
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Let $k$ be a finite field of characteristic $p$. There is only one
characteristic-$p$ local field with residue field $k$, namely
$k((\pi))$, where $\pi$ is transcendental, and there is a "smallest"
characteristic-$0$ local field with residue field $k$, namely the
degree $a$ degree-$a$ unramified extension $K$ of $\mathbb{Q}_p$, where $q=p^a$ is
the cardinality of $k$.
Every characteristic-$0$ local field with residue field $k$ is a
finite totally ramified extension of $K$, and every finite totally
ramified extension of $K$ has residue field $k$.
As $K$ has only finitely many extensions of any given degree, we might
ask for the number of totally ramified extensions $L|K$ of given
degree $[L:K]=n$. Serre's "mass formula" (Comptes rendus 1978),
says that there are exactly $n$ such extensions, when counted
properly. This formula was also proved by Krasner by his methods.
Let Serre explain:
"Let $K$ be a local field, with finite residue
field with $q$ elements. Let $n$ be a positive integer, and let
$\Sigma_n$ be the set of all totally ramified extensions of $K$ of
degree $n$ contained in a given separable closure of $K$. If
$(n,p)=1$, it is easy to show that $\text{Card}(\Sigma_n)=n$. If $L$
belongs to $\Sigma_n$, put $c(L)=d(L)-n+1$, where $d(L)$ is the
valuation of the discriminant of $L/K$. Our 'mass formula' is
$\sum_{L\in \Sigma_n} q^{-c(L)}=n$.
We give two proofs. The first one
uses Eisenstein polynomials, while the second one applies the H. Weyl
integration formula to the multiplicative group of a division
algebra." MR0500361 (80a:12018)
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4
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edited Dec 27 2009 at 5:33
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Let $k$ be a finite field of characteristic $p$. There is only one
characteristic-$p$ local field with residue field $k$, namely
$k[[\pi]]$, k((\pi))$, where $\pi$ is transcendental, and there is a "smallest"
characteristic-$0$ local field with residue field $k$, namely the
degree $a$ unramified extension $K$ of $\mathbb{Q}_p$, where $q=p^a$ is
the cardinality of $k$.
Every characteristic-$0$ local field with residue field $k$ is a
finite totally ramified extension of $K$, and every finite totally
ramified extension of $K$ has residue field $k$.
As $K$ has only finitely many extensions of any given degree, we might
ask for the number of totally ramified extensions $L|K$ of given
degree $[L:K]=n$. Serre's "mass formula" (Comptes rendus 1978),
says that there are exactly $n$ such extensions, when counted
properly. This formula was also proved by Krasner by his methods.
Let Serre explain:
"Let $K$ be a local field, with finite residue
field with $q$ elements. Let $n$ be a positive integer, and let
$\Sigma_n$ be the set of all totally ramified extensions of $K$ of
degree $n$ contained in a given separable closure of $K$. If
$(n,p)=1$, it is easy to show that $\text{Card}(\Sigma_n)=n$. If $L$
belongs to $\Sigma_n$, put $c(L)=d(L)-n+1$, where $d(L)$ is the
valuation of the discriminant of $L/K$. Our 'mass formula' is
$\sum_{L\in \Sigma_n} q^{-c(L)}=n$.
We give two proofs. The first one
uses Eisenstein polynomials, while the second one applies the H. Weyl
integration formula to the multiplicative group of a division
algebra." MR0500361 (80a:12018)
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3
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edited Dec 27 2009 at 5:29
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Let $k$ be a finite field of characteristic $p$. There is only one
characteristic-$p$ local field with residue field $k$, namely
$k((\pi))$, k[[\pi]]$, where $\pi$ is transcendental, and there is a "smallest"
characteristic-$0$ local field with residue field $k$, namely the
degree-$a$ degree $a$ unramified extension $K$ of ${\bf Q}_p$, \mathbb{Q}_p$, where $q=p^a$ is
the cardinality of $k$.
Every characteristic-$0$ local field with residue field $k$ is a
finite totally ramified extension of $K$, and every finite totally
ramified extension of $K$ has residue field $k$.
As $K$ has only finitely many extensions of any given degree, we might
ask for the number of totally ramified extensions $L|K$ of given
degree $[L:K]=n$. Serre's ``mass formula'' "mass formula" (Comptes rendus 1978),
says that there are exactly $n$ such extensions, when counted
properly. This formula was also proved by Krasner by his methods.
Let Serre explain. `:
"Let $K$ be a local field, with finite residue
field with $q$ elements. Let $n$ be a positive integer, and let
$\Sigma_n$ be the set of all totally ramified extensions of $K$ of
degree $n$ contained in a given separable closure of $K$. If
$(n,p)=1$, it is easy to show that $\text{Card}(\Sigma_n)=n$. If $L$
belongs to $\Sigma_n$, put $c(L)=d(L)-n+1$, where $d(L)$ is the
valuation of the discriminant of $L/K$. Our 'mass formula' is
$\sum_{L\in\Sigma_n}1/q^{c(L)}=n$. \sum_{L\in \Sigma_n} q^{-c(L)}=n$.
We give two proofs. The first one
uses Eisenstein polynomials, while the second one applies the H. Weyl
integration formula to the multiplicative group of a division
algebra.'' algebra." MR0500361 (80a:12018)
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edited Dec 27 2009 at 5:17
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Let $k$ be a finite field of characteristic $p$. There is only one characteristic-$p$ local field with residue field $k$, namely $k[[\pi]]$, k((\pi))$, where $\pi$ is transcendental, and there is a "smallest" characteristic-$0$ local field with residue field $k$, namely the degree-$a$ unramified extension $K$ of ${\bf Q}_p$, where $q=p^a$ is the cardinality of $k$.
Every characteristic-$0$ local field with residue field $k$ is a finite totally ramified extension of $K$, and every finite totally ramified extension of $K$ has residue field $k$.
As $K$ has only finitely many extensions of any given degree, we might ask for the number of totally ramified extensions $L|K$ of given degree $[L:K]=n$. Serre's ``mass formula'' (Comptes rendus 1978), says that there are exactly $n$ such extensions, when counted properly. This formula was also proved by Krasner by his methods.
Let Serre explain. `Let $K$ be a local field, with finite residue field with $q$ elements. Let $n$ be a positive integer, and let $\Sigma_n$ be the set of all totally ramified extensions of $K$ of degree $n$ contained in a given separable closure of $K$. If $(n,p)=1$, it is easy to show that $\text{Card}(\Sigma_n)=n$. If $L$ belongs to $\Sigma_n$, put $c(L)=d(L)-n+1$, where $d(L)$ is the valuation of the discriminant of $L/K$. Ourmass formula' is $\sum_{L\in\Sigma_n}1/q^{c(L)}=n$. We give two proofs. The first one uses Eisenstein polynomials, while the second one applies the H. Weyl integration formula to the multiplicative group of a division algebra.'' MR0500361 (80a:12018)
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1
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answered Dec 27 2009 at 4:31
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Let $k$ be a finite field of characteristic $p$. There is only one characteristic-$p$ local field with residue field $k$, namely $k[[\pi]]$, where $\pi$ is transcendental, and there is a "smallest" characteristic-$0$ local field with residue field $k$, namely the degree-$a$ unramified extension $K$ of ${\bf Q}_p$, where $q=p^a$ is the cardinality of $k$.
Every characteristic-$0$ local field with residue field $k$ is a finite totally ramified extension of $K$, and every finite totally ramified extension of $K$ has residue field $k$.
As $K$ has only finitely many extensions of any given degree, we might ask for the number of totally ramified extensions $L|K$ of given degree $[L:K]=n$. Serre's ``mass formula'' (Comptes rendus 1978), says that there are exactly $n$ such extensions, when counted properly. This formula was also proved by Krasner by his methods.
Let Serre explain. `Let $K$ be a local field, with finite residue field with $q$ elements. Let $n$ be a positive integer, and let $\Sigma_n$ be the set of all totally ramified extensions of $K$ of degree $n$ contained in a given separable closure of $K$. If $(n,p)=1$, it is easy to show that $\text{Card}(\Sigma_n)=n$. If $L$ belongs to $\Sigma_n$, put $c(L)=d(L)-n+1$, where $d(L)$ is the valuation of the discriminant of $L/K$. Ourmass formula' is $\sum_{L\in\Sigma_n}1/q^{c(L)}=n$. We give two proofs. The first one uses Eisenstein polynomials, while the second one applies the H. Weyl integration formula to the multiplicative group of a division algebra.'' MR0500361 (80a:12018)
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