show/hide this revision's text 4 edited body; deleted 16 characters in body

Let $k$ be your base field, then consider the ring $k[\epsilon]/\epsilon^{n+1}$. The elements of the ring such that $v^2=0$ v^2=1$ are given by the formula just $v=\pm1$. These elements do not span the ring as a vector space over $k$.

show/hide this revision's text 3 deleted 21 characters in body

Let $k$ be your base field, then consider the ring $k[\epsilon]/\epsilon^{n+1}$. The elements of the ring such that $v^2=0$ are given by the formula $v=\pm1$, for $f$ in the ring. v=\pm1$. These elements do not span the ring as a vector space over $k$.

show/hide this revision's text 2 deleted 22 characters in body

Let $k$ be your base field, then consider the ring $k[\epsilon]/\epsilon^{n+1}$. The elements of the ring such that $v^2=0$ are given by the formula $v=\pm1 + f\epsilon^{(n+1)/2}$, v=\pm1$, for $f$ in the ring. These elements do not span the ring as a vector space over $k$.

show/hide this revision's text 1