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The following problem has bothered me for a long time.

Let us imagine a point on the real axis. At the beginning, it is located at point $O$. Then it will "walk" on the real axis randomly in the following way. For every step of the "walk", it will choose a real number $\Delta x$ in uniformly from the interval $[-1,1]$ equiprobably, and [-1,1]$, turn right, and move $\Delta x$ unit. Once it move to reaches the left side of the point $O$, it will "die" immediately.

Our task is find out the probability of the point "live" is alive after $n$ steps of "walk" $P_n$. I guess that $P_n=\frac{(2n)!}{4^n (n!)^2}$. But n!)^2}$, but I can't prove that it is correct this or explain why it is true.

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Something look simple but has bothered me for a long time in Probability TheoremA random walk with uniformly distributed steps

Hi! ^-^ I'm a new.

The following problem bothered me for a long time.

Now let

Let us imagine a point on the real axis. At the beginning, it is located at point $O$. Then it will "walk" on the real axis randomly. For every step of the "walk", it will choose a real number $\Delta x$ in interval $[-1,1]$ equiprobably, and turn right and move $\Delta x$ unit. Once it move to the left side of the point $O$, it will "die" immediately.

Our task is find out the probability of the point "live" after $n$ steps of "walk" $P_n$. I guess that $P_n=\frac{(2n)!}{4^n (n!)^2}$. But I can't prove that it is correct or explain why.

Thanks for your browse!

( P.s. My English is really poor. :( )

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Something look simple but has bothered me for a long time in Probability TheormTheorem

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