For $0 \le lt k \lt n$,
$$\binom{n}{k} = \frac{n}{n-k}\binom{n-1}{k}$$
How k-subsets of [n], marked dark green in the rows, come from k-subsets of [n-1] after n-fold duplication and rearrangement:
Exactly $n-k$ times:

By induction, a base case, and case taking $k=n$ which we already know due to case and $k=0$: k=0$ for granted: $$\binom{n}{k} = \frac{n}{(n-k)} \frac{(n-1)!}{(n-1-k)!\ k!} = \frac{n!}{(n-k)!\ k!}$$


