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For $0 \le lt k \lt n$,

$$\binom{n}{k} = \frac{n}{n-k}\binom{n-1}{k}$$


How k-subsets of [n], marked dark green in the rows, come from k-subsets of [n-1] after n-fold duplication and rearrangement:

alt text Exactly $n-k$ times:

alt text
By induction, a base case, and case taking $k=n$ which we already know due to case and $k=0$: k=0$ for granted: $$\binom{n}{k} = \frac{n}{(n-k)} \frac{(n-1)!}{(n-1-k)!\ k!} = \frac{n!}{(n-k)!\ k!}$$

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For $0 \binom{n}{k} le k \lt n$,

$$\binom{n}{k} = \frac{n!}{(n-k)!\ k!} frac{n}{n-k}\binom{n-1}{k}$$


How k-subsets of [n], marked dark green in the rows, come from k-subsets of [n-1] after n-fold duplication and rearrangement:

alt text Exactly $n-k$ times:

alt text
By induction, a base case, and case $

Induction step for k=n$ which we already know due to case $k < n$:

alt text

Hint: k=0$: $$\frac{n}{(n-k)} $\binom{n}{k} = \frac{n}{(n-k)} \frac{(n-1)!}{(n-1-k)!\ k!} = \frac{n!}{(n-k)!\ k!}$$

show/hide this revision's text 1 [made Community Wiki]

$$ \binom{n}{k} = \frac{n!}{(n-k)!\ k!} $$

Induction step for $k < n$:

alt text

Hint: $$\frac{n}{(n-k)} \frac{(n-1)!}{(n-1-k)!\ k!}$$