Let $q$ be a power of prime number $p$ and let $F_{q^2}$ be a finite field of order $q^2$. Suppose that "-" be a conjugation operation that is defined as follow:
$-:F_{q^2} \longrightarrow F_{q^2}$
$x \longmapsto x^q$
Suppose that we define Hermitian inner product over $F_{q^2}$ as follow:
$(x,y)=x.\bar{y}$
Let $C$ be a cyclic code of length n over $F_{q^2}$ with the generator polynomial $g(x)$ and let $\bar{C}=\lbrace \bar{c} : c \in C \rbrace$ be the conjugate code of $C$.
It is obvious that $\bar{C}$ is also a cyclic code.
Is it possible to determine the generator polynomial of $\bar{C}$ from $g(x)$?
