They are using continuous cohomology, so that $$H^n(G,M) = \varinjlim H^n(G/H,M^H)$$ if $G$ is topological and $M$ is continuous discrete (thanks Arjit) $G$-module (the limit runs over open compact subgroups $H$ of $G$). Look in p. 38 for the definition.
They are using continuous cohomology, so that $$H^n(G,M) = \varinjlim H^n(G/H,M^H)$$ if $G$ is topological and $M$ is continuous $G$-module (the limit runs over open compact subgroups $H$ of $G$). Look in p. 38 for the definition.