Not every finite index subgroup is open, but closed subgroups of finite index are open.
So you just have to check that if the stabilizer is closed, which is not too difficult! :)that would be sufficient...
|
2 | deleted 28 characters in body | ||
|
|
||||
|
|
1 |
|
||
|
Not every finite index subgroup is open, but closed subgroups of finite index are open. So you just have to check that the stabilizer is closed, which is not too difficult! :) |
||||
