This proves the Minkowski version of the Pythagorean theorem:
$c^2 = a^2 - b^2$
|
1 | [made Community Wiki] | ||
|
|
||||
|
|
1 | [made Community Wiki] | ||
|
This proves the Minkowski version of the Pythagorean theorem:
$c^2 = a^2 - b^2$ |
||||
