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Discrete-analytic functionsI do not know if such concept already exists but lets consider functions which are equal to its Newton series. We know that functions which are equal to their Taylor series are called analytic, so lets call functions that are equal to their Newton series "discrete analytic". The formula is alalogious to Taylor series but uses finite differences instead of dirivatives, so for any discrete-analytic function: $$f(x) = \sum_{k=0}^\infty \binom{x-a}k \Delta^k f\left (a\right)$$ It is known that for a functional equation $\Delta f=F\, $there are infinitely many solutions which differ by any 1-periodic function. But it appears that there is only one (up to a constant) discrete-analytic solution, i.e. all discrete-analytic solutions differ only by a constant term. Thus I have the following questions:
For the second part of the question, as I know there is at least one one similar attempt, the Mueller's formula: If $$\lim_{x\to{+\infty}}\Delta f(x)=0$$ then $$f(x)=\sum_{n=0}^\infty\left(\Delta f(n)-\Delta f(n+x)\right)$$ although it seems not to be universal and I do not now whether it is always useful.
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