A simple proof of the Weyl algebra's rigidity.
I am wondering if there is a nice presentation of the Hochschild cohomology of $A_n$ the Weyl algebra. It is known that $H^m(A_n,A_n)=0$ for $m>0$, and thus it is rigid. A proof can be found in Sridharan, but this proof seems to be doing a lot more and is fairly complicated.
I was wondering if there was a simpler way to see this fact specifically. Essentially, I am being a bit lazy.