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Value of a Vieta-like productsGeneralized Vieta-product |
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It's known that The terms in the product approaches 1, the same holds for the following convergent series, with $\phi$ the golden ratio $$S_1 = {\sqrt{1}\over\phi}{\sqrt{1+\sqrt{1}}\over\phi}{\sqrt{1+\sqrt{1+\sqrt{1}}}\over\phi}\dots$$ Is there a simpler formula for $S_n$? Let $$S_n = {\sqrt{n}\over c_n}{\sqrt{n+\sqrt{n}}\over c_n}\dots$$ Where $c_n$ is the solution to the equation $x=\sqrt{n+x}$ Is it possible to extend there a simpler formula for $S_n$ to the positive reals? S_n$? What is the asymptotics asymptotic behavior (Big-O) of $S(n)$ ?S_n$ as $n->\infty$?
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It's known that The terms in the product approaches 1, the same holds for the following convergent series, with $\phi$ the golden ratio $$S_1 = {\sqrt{1}\over\phi}{\sqrt{1+\sqrt{1}}\over\phi}{\sqrt{1+\sqrt{1+\sqrt{1}}}\over\phi}\dots$$ Is there a simpler formula for $S_n$? $$S_n = {\sqrt{n}\over c_n}{\sqrt{n+\sqrt{n}}\over c_n}\dots$$ Where $c_n$ is the solution to the equation $x=\sqrt{n+x}$ Is it possible to extend $S_n$ to the positive reals? What is the asymptotics of $S(n)$ ?
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