The Fibonacci word is one of the Sturmian words, so its complexity is $n+1$, that is the number of different subwords of length $n$ is $n+1$. So most words are not subwords of the Fibonacci word. There are, as far as I remember 12 different but equivalent definitions of Sturmian words. Some of them give restrictions on possible subwords (see Algebraic combinatorics on words by LothairLothaire, and an article by Berstel there).
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The Fibonacci word is one of the Sturmian words, so its complexity is $n+1$, that is the number of different subwords of length $n$ is $n+1$. So most words are not subwords of the Fibonacci word. There are, as far as I remember 12 different but equivalent definitions of Sturmian words. Some of them give restrictions on possible subwords (see Algebraic combinatorics on words by Lothair, and an article by Berstel there). |
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