show/hide this revision's text 2 zeros

Up to $10^6$:

$\sigma(8n+1) \mod 4 = OEIS A001935(n) \mod 4$

A001935 Number of partitions with no even part repeated

Is this true in general?

It would mean relation between restricted partitions of $n$ and divisors of $8n+1$.

Another one up to $10^6$ is:

$\sigma(4n+1) \mod 4 = A001936(n) \mod 4$

A001936 Expansion of q^(-1/4) (eta(q^4) / eta(q))^2 in powers of q

$\sigma(n)$ is sum of divisors of $n$.

sigma(8n+1) mod 4 starts: 1, 1, 2, 3, 0, 2, 1, 0, 0, 2, 1, 2, 2, 0, 2, 1, 0, 2, 0, 2, 0, 3, 0, 0, 2, 0, 0, 0, 3, 2

sigma(4n+1) mod 4 starts: 1, 2, 1, 2, 2, 0, 3, 2, 0, 2, 2, 2, 1, 2, 0, 2, 0, 0, 2, 0, 1, 0, 2, 0, 2, 2

Update

Up to 10^7

A001935 mod 4 is zero for n = 9m+4 or 9m+7

A001936 mod 4 is zero for n = 9m+5 or 9m+8

Question about computability

show/hide this revision's text 1

Up to $10^6$: $\sigma(8n+1) \mod 4 = OEIS A001935(n) \mod 4$ (Number of partitions with no even part repeated )

Up to $10^6$:

$\sigma(8n+1) \mod 4 = OEIS A001935(n) \mod 4$

A001935 Number of partitions with no even part repeated

Is this true in general?

It would mean relation between restricted partitions of $n$ and divisors of $8n+1$.

Another one up to $10^6$ is:

$\sigma(4n+1) \mod 4 = A001936(n) \mod 4$

A001936 Expansion of q^(-1/4) (eta(q^4) / eta(q))^2 in powers of q

$\sigma(n)$ is sum of divisors of $n$.

sigma(8n+1) mod 4 starts: 1, 1, 2, 3, 0, 2, 1, 0, 0, 2, 1, 2, 2, 0, 2, 1, 0, 2, 0, 2, 0, 3, 0, 0, 2, 0, 0, 0, 3, 2

sigma(4n+1) mod 4 starts: 1, 2, 1, 2, 2, 0, 3, 2, 0, 2, 2, 2, 1, 2, 0, 2, 0, 0, 2, 0, 1, 0, 2, 0, 2, 2