Edit.Thanks Igor, sleepless, Douglas for your comments,and apologies for not being clear!Let me attempt a sharper question.
Let the density of the polyhedron $P$ be half that of water,I seek a $P$ that has $k>1$ distinct stable floating orientations.So $P$ is unlike a sphere, which is stable in any orientation(Ulam's question is: Is the sphere the only such convex body?).And $P$ is unlike a boat-hull shape that is designed to have a unique stableorientation, i.e., is monostatic.In each of $P$'s stable orientations, some face's normal vector $n_i$is vertical, perpendicular to the water level, pointing up.So if you look down from above, you see that face $F_i$.
That is the basic question.Now some embellishments:
It is not essential that $\rho=\frac{1}{2}$ exactly.Let's say,$\rho \in [\frac{1}{4},\frac{3}{4}]$.It is not essential that each of the normal vectors $n_i$be exactly vertical.It just needs to be clear which face is "up."Let's say that $n_i$ should make an angle of $\le \delta$ withthe vertical $(0,0,1)$, and no other face normal $n_j$makes an angle of $\le 3 \delta$ with the vertical.if $P$ is placed in the water at an arbitrary orientation,it should stabilize into one of its $k$ stable positionswith equal probability.So the total solid angle of orientations that lead to eachof the $k$ distinct stable positions should be $4 \pi / k$.Were these conditions satisfied, one could place $P$ in a glass cylinder half full ofliquid, shake it, wait, and look down through the cylinder top to see the numbered up-face.

