Let us call $[A_n,B_n]$ the segment at time $n$. Then, for all $n \ge 1$:
1) $A_n$ is chosen uniformly on the sphere circle of radius $1$ centred at $A_{n-1}$ (independtly independently of the past).
2) $B_n=A_{n-1}$.
Therefore $A_n$ performs a simple random walk.

