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I am wondering if Let $BS(1,4) = \langle a,b\mid bab^{-1}=a^4 \rangle$ can G$ be embedded into the following a group generated by $a_0, a_1, a_2$ with relations: $a_0 a_1 a_0^{-1}=a_1^4$ $a_1 a_2 a_1^{-1}=a_2^4$ $a_2 a_0 a_2^{-1}=a_0^4$ I am wondering if $BS(1,4)=\langle a,b:bab^{-1}=a^4\rangle$ is embedded into G via $a\mapsto a_1$, $b\mapsto a_0$ Remark: the group is constructed in analogy to Higman group |
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Let I am wondering if $G$ BS(1,4) = \langle a,b\mid bab^{-1}=a^4 \rangle$ can be a embedded into the following group generated by $a_0, a_1, a_2$ with relations: $a_0 a_1 a_0^{-1}=a_1^4$ $a_1 a_2 a_1^{-1}=a_2^4$ $a_2 a_0 a_2^{-1}=a_0^4$ I am wondering if $BS(1,4)=$ is embedded into G via $a\mapsto a_1$, $b\mapsto a_0$ Remark: the group is constructed in analogy to Higman group |
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I am wondering if Let $BS(1,4)= \langle a,b:bab^{-1}=a^4 \rangle$ can G$ be embedded into the following a group generated by $a_0, a_1, a_2$ with relations: $a_0 a_1 a_0^{-1}=a_1^4$ $a_1 a_2 a_1^{-1}=a_2^4$ $a_2 a_0 a_2^{-1}=a_0^4$ I am wondering if $BS(1,4)=$ is embedded into G via $a\mapsto a_1$, $b\mapsto a_0$ Remark: the group is constructed in analogy to Higman group |
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