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Post Undeleted by Peter McNamara
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In fact, we may embed Let us first suppose that gs is not elliptic. Choose an embedding of G into GLn to reduce to (ℂ). Then by our assumption, gs has an eigenvalue of norm greater than one, let λ be the case where G=GLabsolute value of such an eigenvalue. Suppose for want of contradiction that the conjugacy class of gs contained an elliptic element a in its closure. WLOG a is in the special unitary group SUn. Let h be in the conjugacy class of gs. Then h has an eigenvalue of absolute value λ. Letting v be an eigenvector, we see that |(h-a)v| is at least (all relevant notions such as λ-1)|v|, so |h-a|≥λ-1, a contradiction. Now suppose that gs is elliptic. We may replace G by the Jordan decomposition and centraliser of gs is G, which is also reductive. So WLOG, gs is central in G. Now the notion Zariski closure of ellipticality are inherited from the GLn case)group generated by gu is a one-dimensional unipotent subgroup of G. Let E be a non-zero element in its lie algebra. This is a nilpotent element. Then by the Jacobson-Morozov theorem, where you say you have already proven this factwe can extend E to a sl2 triple E,F,H in Lie(G). Now consider conjugation by elements of the form exp(tH) with t real. This shows that gs is in the closure of the conjugacy class of g, and we're done. |
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Post Deleted by Peter McNamara
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