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Is there "A gentleman never chooses a basis-free proof that finite dimensional vector spaces are reflexive?basis."

Around these parts, the aphorism "A gentleman never chooses a basis," has become popular.

Is there a gentlemanly way to prove that the natural map from V to V** is surjective if V is a finite dimensional vector spacedimensionsal?

As in life, without choosing the exact standards for gentlemanliness are a basis?bit vague. Some arguments seem to be implicitly pick basesbasis. I'm hoping there's an argument which is unambiguously free of choicesunambigously gentlemanly.

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"A gentleman never chooses Is there a basis."basis-free proof that finite dimensional vector spaces are reflexive?

Around these parts, the aphorism "A gentleman never chooses a basis," has become popular.

Is there a gentlemanly way to prove that the natural map from V to V** is surjective if V is a finite dimensionsal?

As in lifedimensional vector space, the exact standards for gentlemanliness are without choosing a bit vague. basis?

Some arguments seem to be implicitly pick basisbases. I'm hoping there's an argument which is unambigously gentlemanlyunambiguously free of choices.

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Around these parts, the aphorism "A gentleman never chooses a basis," has become popular.

Is there a gentlemanly way to prove that the natural map from V to V** is surjective if V is finitely finite dimensionsal?

As in life, the exact standards for gentlemanliness are a bit vague. Some arguments seem to be implicitly pick basis. I'm hoping there's an argument which is unambigously gentlemanly.

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