show/hide this revision's text 2 i know it's a hack, still let the matrix look like a matrix

I've always seen the following identity for the determinant of block matrices as a 'joke'

$\rm{det}\left( \det\left( \begin{array}{cc}A begin{array}{cc} A & B \newline C & D \end{array} \right) = \det(AD-BC)$

show/hide this revision's text 1 [made Community Wiki]

I've always seen the following identity for the determinant of block matrices as a 'joke'

$\rm{det}\left( \begin{array}{cc}A & B \ C & D \end{array} \right) = \det(AD-BC)$