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(a,b) <= (a',b') iff b <= a' or (b' = b and a <= a') where a<=b a≤b and a'<=b'. a'≤b'. Has any one seen this order?

I have been mucking round with orders, and this is the order that I found I needed. I would like to know if it is defined somewhere else, it is kind of difficult to search for such things.

*EDIT*

The only application I have used it for at the moment is a totally ordered domain (e.g. '$a,b \in R $'), but I think it would extend to a partially ordered lattice.

Consider two intervals (a,b) (a',b'), if one is clearly better than the other, i.e. b<=a' b≤a' then a<=b<=a'<=b' a≤b≤a'≤b' it is better. But if the interval has the same least upper bound where b=b', then only the greatest lower bound matters, so a <= a'.

The order that this creates is why I defined it. for instance, given 3 reals {1,2,3} we use a function that defines an interval on each where f(1) = [0,2] f(2) = [1,3] and f(3) = [2,4]. Using this order we can then state that f(1) || f(2) and f(2) || f(3) but f(1) < f(3).

The goal of this order is that it should create a lattice as well.

Thanks for your help.

EDIT

I missed a really important part, sorry. This is based on intervals so a <= b and a' <= b' must be true.

(a,b) <= (a',b') iff b <= a' or (b' = b and a < a') where a <= b AND a' <= b'

show/hide this revision's text 3 Gave more of a stroy.; edited title

(a,b) <= (a',b') iff b <= a' or (b' = b and a < <= a') where a<=b and a'<=b'. Has any one seen this order?

I have been mucking round with orders, and this is the order that I found I needed. I would like to know if it is defined somewhere else, it is kind of difficult to search for such things.

*EDIT*

The only application I have used it for at the moment is a totally ordered domain (e.g. '$a,b \in R $'), but I think it would extend to a partially ordered lattice.

Consider two intervals (a,b) (a',b'), if one is clearly better than the other, i.e. b<=a' then a<=b<=a'<=b' it is better. But if the interval has the same least upper bound where b=b', then only the greatest lower bound matters, so a <= a'.

The order that this creates is why I defined it. for instance, given 3 reals {1,2,3} we use a function that defines an interval on each where f(1) = [0,2] f(2) = [1,3] and f(3) = [2,4]. Using this order we can then state that f(1) || f(2) and f(2) || f(3) but f(1) < f(3).

The goal of this order is that it should create a lattice as well.

Thanks for your help.

EDIT

I missed a really important part, sorry. This is based on intervals so a <= b and a' <= b' must be true.

(a,b) <= (a',b') iff b <= a' or (b' = b and a < a') where a <= b AND a' <= b'

show/hide this revision's text 2 added 200 characters in body; added 2 characters in body; edited title

(a,b) <= (a',b') iff b <= a' or (b' = b and a < a'). a') where a<=b and a'<=b'. Has any one seen this order?

I have been mucking round with orders, and this is the order that I found I needed. I would like to know if it is defined somewhere else, it is kind of difficult to search for such things. Thanks for your help.

EDIT

I missed a really important part, sorry. This is based on intervals so a <= b and a' <= b' must be true.

(a,b) <= (a',b') iff b <= a' or (b' = b and a < a') where a <= b AND a' <= b'

show/hide this revision's text 1